为了避免在UI线程中执行与http相关的东西,我将我的代码迁移到asynctask中,在此之前,它在3.0之前的版本上运行良好 - 但是,在字面上复制粘贴代码后,它开始给出invalid index, size is 0 exception
。每当我需要使用我应用调用的方法时——
new dataRetrievalViaAsyncTask().execute(url, null, null);
——
下面怎么了?
class dataRetrievalViaAsyncTask extends AsyncTask<String, Void, Void>
{
@Override
protected void onPreExecute()
{
super.onPreExecute();
}
@Override
protected Void doInBackground(String... f_url)
{
Log.i("tag", "inside doInBackground");
String url2 = f_url[0];
Log.i("tag", url2);
HttpClient httpclient = new DefaultHttpClient();
Log.i("tag", "done : HttpClient httpclient = new DefaultHttpClient();");
HttpPost httppost = new HttpPost(url2);
Log.i("tag", "done : HttpPost httppost = new HttpPost(url);");
try
{
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
Log.i("tag", "done : httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));");
HttpResponse response = httpclient.execute(httppost);
Log.i("tag", "done : HttpResponse response = httpclient.execute(httppost);");
HttpEntity entity = response.getEntity();
Log.i("tag", "done : HttpEntity entity = response.getEntity();");
is = entity.getContent();
Log.i("tag", "after : is = entity.getContent();");
} catch (Exception e)
{
Log.e("log_tag", "Error in http connection", e);
}
// convert response to string
return null;
}
protected void onPostExecute()
{
try
{
Log.i("tag","before : BufferedReader reader = new BufferedReader(new Inp");
BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
sb = new StringBuilder();
sb.append(reader.readLine() + "n");
String line = "0";
while ((line = reader.readLine()) != null)
{
sb.append(line + "n");
}
is.close();
result = sb.toString();
} catch (Exception e)
{
Log.e("log_tag", "Error in http connection", e);
}
try
{
Log.i("tag", "before : jsons ");
jArray = new JSONArray(result);
JSONObject json_data = null;
Log.i("tag", Integer.toString(jArray.length()));
for (int i = 0; i < jArray.length(); i++)
{
json_data = jArray.getJSONObject(i);
uid = json_data.getInt("uid");
item1= json_data.getString("item1");
item2 = json_data.getString("item2");
item3 = json_data.getString("item3");
item4 = json_data.getString("item4");
item5 = json_data.getString("item5");
item6 = json_data.getString("item6");
favorited = json_data.getString("favorited");
currentList.add(new itemClass(uid, item1 item2)); //there is a constructor for this in the itemClass
itemClass toSendToOffline = new itemsClass(uid, item1, item2, item3, item4, item5, item6, favorited);
myDBHelper.insertFromOnlineToDBtoSendToOffline();
}
} catch (JSONException e1)
{
Toast.makeText(getBaseContext(), "Not Found", Toast.LENGTH_LONG).show();
} catch (ParseException e1)
{
e1.printStackTrace();
}
super.onPostExecute(null);
}
}
(主要是代码停在——
HttpResponse response = httpclient.execute(httppost);
我看不到 nameValuePair 变量在任何地方初始化,这实际上会导致问题。
class dataRetrievalViaAsyncTask extends AsyncTask<Void, Void, String>
{
String URL = "";
public dataRetrievalViaAsyncTask( String url )
{
URL = url;
}
@Override
protected void onPreExecute()
{
}
@Override
protected String doInBackground(Void... f_url)
{
String result="";
try
{
result=fetchdataFromServer(URL);
}
catch (JSONException e)
{
e.printStackTrace();
}
return result;
}
protected void onPostExecute(String result)
{
// See your results as string //result
}
public JSONObject getJsonObjectToRequestToServer(String plid) throws JSONException
{
JSONObject parms = new JSONObject();
parms.put("user_id", "");
parms.put("app_key", "xyz");
parms.put("secret", "abc");
parms.put("token", "");
parms.put("playurl", "1");
parms.put("mode", "playlistdetail");
parms.put("playlist_id", plid);
return parms;
}
public String fetchdataFromServer(String url) throws JSONException
{
String stringresponce = null;
try
{
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(URL);
JSONObject parms = getJsonObjectToRequestToServer("1");
StringEntity se;
se = new StringEntity(parms.toString());
httpPost.setEntity(se);
httpPost.setHeader("Content-type", "application/json");
@SuppressWarnings("rawtypes")
ResponseHandler responseHandler = new BasicResponseHandler();
stringresponce = httpClient.execute(httpPost, responseHandler);
}
catch (UnsupportedEncodingException e)
{
e.printStackTrace();
}
catch (ClientProtocolException e)
{
e.printStackTrace();
}
catch (IOException e)
{
e.printStackTrace();
}
return stringresponce;
}
}
将此代码放入您的代码中并传递您需要的参数 这是我请求服务器并从结果变量中获取 JSON 响应的方式 当我通过制作 JSON 对象将它们转换为字符串时,将参数传递给您的 URL
然后像这样执行...
dataRetrievalViaAsyncTask asyncTask=new dataRetrievalViaAsyncTask(Yoururl);
asyncTask.execute();
希望这会有所帮助,如果你有一些问题,请在这里发布,谢谢......