我正在尝试仅在PHP中登录一个密码，因为我有一个" Pocket Server"总是会更改域（我使用ngrok，所以我不必portforward），而且我需要一个域示踪剂，所以我的用户始终知道指向口袋服务器的链接，我已经有一个网站，我想制作它，以便我不必制作复杂的登录系统，我想仅仅通过一个来识别自己密码，别无其他，网站很简单，它具有文本框和一些文本
目标：
- 具有简单的密码登录
- 如果我登录，我可以更改公共网站上显示的域
到目前为止我的代码：
<!DOCTYPE html>
<html>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<title>Killer Doge</title>
<link rel="stylesheet" href="style.css">
</head>
<body>
<h1>Killer Doge Tracer (Link changes daily)</h1>
<?php
$text = "domain";
?>
<p>Current domain:</p>
<?php
echo $text;
?>
<br>
<?php echo '<input type="text" name="name1" value="'.$admin.'">';
If ($admin == "694205") {
echo yees;
}
?>
</body>
</html>
这几乎是@maarten van Middelaar所说的，但是有点复杂。
我将尝试通过代码注释解释：
<?php // always start the session first.
if (session_status() == PHP_SESSION_NONE) {
session_start();
}
//Check if loginform was submitted:
if(isset($_POST['admin'])){
if($_POST['admin'] == '12345678'){
//user logged in correctly, store in session so you don't get instantly logged out:
$_SESSION['loggedIn'] = "logged in!";
}
}
//check if domainchanger form was submitted and user is logged in
if(isset($_POST['newdomain']) && isset($_SESSION['loggedIn'])){
$newDomain = $_POST['newdomain'];
//TODO: Set new domain in the database so your website can retrieve it.
}
//Check if user is not logged in already
if(!isset($_SESSION['loggedIn'])):
//Show login form if not logged in
?>
<form method="post">
<input type='text' name='admin' />
<input type='submit' value="log in!" />
</form>
<?php else:
//if logged in, show domain changer thing
//Show the current domain as the default value for the input
//TODO: make database connection here to get current domain
//structure: Create query to get current domain -> $currentDomain = dbresult
?>
<form method="post">
<input type="text" name="newdomain" value="<?= $currentDomain ?>" />
<input type='submit' value="change domain!"/>
</form>
<?php endif ?>
我希望这一切都清楚。试图尽可能逐步进行。如果您有任何疑问，请告诉我：）