我想知道 Mapstruct 是否以及如何帮助映射具有双向关系的 ojects(在我的例子中是一对多(:
public class A{
private Set<B> listB;
}
public class B{
private A a;
}
从/到实体的映射会产生StackOverflowError
。(我希望这会发生(。另一方面,关闭的 Mapstruct 问题 469 和 1163 似乎暗示 mapstruct 不会直接支持它。我尝试了这个例子:
https://github.com/mapstruct/mapstruct-examples/tree/master/mapstruct-mapping-with-cycles
但这根本行不通。无论是否应用"CycleAvoidingMappingContext",堆栈溢出错误都保持不变。
那么如何使用循环和利用mapstruct映射对象呢?(我想避免完全手动映射(
为了使映射正常工作,您可以尝试使用以下映射器:
@Mapper
public interface MyMapper {
A map(A a, @Context CycleAvoidingMappingContext context);
Set<B> map(Set<B> b, @Context CycleAvoidingMappingContext context);
B map(B b, @Context CycleAvoidingMappingContext context);
}
如果从Set<B>
映射到Set<B>
的方法不存在,则不会映射A
中的集合。
与此同时,我找到了一个解决方案:首先,我忽略有问题的字段并将其映射到"AfterMapping"中。就我而言,我也想独立映射孩子。就我而言,@Context
仅包含一个Boolean
(boolean
不起作用(,它告诉我进入循环的位置(startedFromPru
pru 是父级(:
父级映射器(包含一组许可证(:
@Mapper(componentModel = "spring", uses = {DateTimeMapper.class, LicenseMapper.class, CompanyCodeMapper.class, ProductHierarchyMapper.class})
public abstract class ProductResponsibleUnitMapper {
@Autowired
private LicenseMapper licenseMapper;
@Mappings({@Mapping(target = "licenses", ignore = true)})
public abstract ProductResponsibleUnit fromEntity(ProductResponsibleUnitEntity entity, @Context Boolean startedFromPru);
@Mappings({@Mapping(target = "licenses", ignore = true)})
public abstract ProductResponsibleUnitEntity toEntity(ProductResponsibleUnit domain, @Context Boolean startedFromPru);
@AfterMapping
protected void mapLicenseEntities(ProductResponsibleUnit pru, @MappingTarget ProductResponsibleUnitEntity pruEntity, @Context Boolean startedFromPru){
if(startedFromPru) {
pruEntity.getLicenses().clear(); //probably not necessary
pru.getLicenses().stream().map(license -> licenseMapper.toEntity(license, startedFromPru)).forEach(pruEntity::addLicense);
}
}
@AfterMapping
protected void mapLicenseEntities(ProductResponsibleUnitEntity pruEntity, @MappingTarget ProductResponsibleUnit pru, @Context Boolean startedFromPru){
if(startedFromPru) {
pru.getLicenses().clear(); //probably not necessary
pruEntity.getLicenses().stream().map(licenseEntity -> licenseMapper.fromEntity(licenseEntity, startedFromPru)).forEach(pru::addLicense);
}
}
}
儿童测绘仪:
@Mapper(componentModel = "spring", uses = { DateTimeMapper.class, CompanyCodeMapper.class, ProductHierarchyMapper.class,
CountryCodeMapper.class })
public abstract class LicenseMapper {
@Autowired
private ProductResponsibleUnitMapper pruMapper;
@Mappings({ @Mapping(source = "licenseeId", target = "licensee"), @Mapping(target = "licensor", ignore = true) })
public abstract License fromEntity(LicenseEntity entity, @Context Boolean startedFromPru);
@Mappings({ @Mapping(source = "licensee", target = "licenseeId"), @Mapping(target = "licensor", ignore = true) })
public abstract LicenseEntity toEntity(License domain, @Context Boolean startedFromPru);
@AfterMapping
protected void mapPru(LicenseEntity licenseEntity, @MappingTarget License license,
@Context Boolean startedFromPru) {
//only call ProductResponsibleUnitMapper if mapping did not start from PRU -> startedFromPru is false
if (!startedFromPru) {
license.setLicensor(pruMapper.fromEntity(licenseEntity.getLicensor(), startedFromPru));
}
}
@AfterMapping
protected void mapPru(License license, @MappingTarget LicenseEntity licenseEntity,
@Context Boolean startedFromPru) {
//only call ProductResponsibleUnitMapper if mapping did not start from PRU -> startedFromPru is false
if (!startedFromPru) {
licenseEntity.setLicensor(pruMapper.toEntity(license.getLicensor(), startedFromPru));
}
}