我创建了一个登录屏幕,以便在输入有效密码时对 excel 工作簿进行身份验证。
代码如下:
Private Sub CommandButton1_Click()
name_selected = ComboBox1.Text
pwd_entered = TextBox2.Text
validation_sheet = "Z"
act_p_col_num = 3
Application.Visible = True
For validation_check = 2 To Worksheets(validation_sheet).Cells(Rows.Count, 1).End(xlUp).Row - 1
If (Worksheets(validation_sheet).Cells(validation_check, 1) = name_selected) Then
bk_pd = Worksheets(validation_sheet).Cells(validation_check, act_p_col_num).Value
If (bk_pd = pwd_entered) Then
Worksheets("INDIVIDUAL_TRACKER").Select
MsgBox ("Authentication successful")
UserForm1.Hide
'Set UserForm1.Visible = False
Else
Application.Visible = False
MsgBox ("Please enter a valid password! Account will be locked after 3 tries")
TextBox2.Text = ""
End If
End If
Next validation_check
End Sub
但是,已经尝试使用此unload me
命令和userform1.hide
命令,这仍然给我抛出运行时错误424,需要对象。
我的目标是在身份验证通过后转到工作簿,并且userform
应自动关闭。
有人可以帮助我解决这个问题吗?
我的猜测是 for 循环的下一次迭代是实际导致问题的原因。您尝试访问 if 语句上的文本框时,窗体已卸载。
尝试包括该行
Exit For
Unload Me
后
洗牌application.visible=True
线已经解决了目的。在正确的地方使用它使它运行良好。使用Exit For
是一个额外的优势。
Private Sub CommandButton1_Click()
name_selected = ComboBox1.Text
pwd_entered = TextBox2.Text
validation_sheet = "Z"
act_p_col_num = 3
Application.Visible = True
For validation_check = 2 To Worksheets(validation_sheet).Cells(Rows.Count, 1).End(xlUp).Row - 1
If (Worksheets(validation_sheet).Cells(validation_check, 1) = name_selected) Then
bk_pd = Worksheets(validation_sheet).Cells(validation_check, act_p_col_num).Value
If (bk_pd = pwd_entered) Then
Unload Me
'UserForm1.Hide
'Set UserForm1.Visible = False
Application.Visible = True
Worksheets("INDIVIDUAL_TRACKER").Select
MsgBox ("Authentication successful")
Exit For
Else
'Application.Visible = False
MsgBox ("Please enter a valid password! Account will be locked after 3 tries")
TextBox2.Text = ""
End If
End If
Next validation_check
End Sub
感谢所有对这个问题有所了解的人。这是一次很好的头脑风暴。谢谢大家。该问题现已解决。