我以这样的方式发送请求:
let task = URLSession.shared.dataTask(with: request) { data, response, error in
guard let data = data, error == nil else {
// check for fundamental networking error
print("error=(String(describing: error))")
completion(nil)
return
}
print("********_Respone status code is: ",(response as! HTTPURLResponse).statusCode)
print("********_Respone url code is: ",response?.url as Any )
do {
let json = try JSONSerialization.jsonObject(with: data, options: .allowFragments) as! [String: Any]
let res:HTTPURLResponse = response as! HTTPURLResponse
print(json)// yessssssssss goooood
} catch {
completion(nil)
return
}
}
task.resume()
当响应是字典时,它正常工作,但是当我的响应是一个数组时,显示此错误:
在
请帮助我解决此问题。
一旦 qson questerialize ,并省略了选项, Array
和 Dictionary
不是 n em> fragmented 。然后可选绑定结果。
do {
let json = try JSONSerialization.jsonObject(with: data)
if let jsonArray = json as? [[String:Any]] {
print("json is array", jsonArray)
} else if let jsonDictionary = json as? [String:Any] {
print("json is dictionary", jsonDictionary)
} else {
print("This should never be displayed")
}
} ...
如果结果应该仅是数组或字典,则可以将结果强制为字典并删除最后一个else
子句
do {
let json = try JSONSerialization.jsonObject(with: data)
if let jsonArray = json as? [[String:Any]] {
print("json is array", jsonArray)
} else {
let jsonDictionary = json as! [String:Any]
}
} ...