蟒蛇网页刮美丽的汤并添加到列表中

Question

我正在尝试学习使用Python和BeautifulSoup进行网页抓取。我的问题是，当我尝试将"抓取"项目添加到新列表中时，当我打印列表时，仅显示相关标签中的最后一个条目。如何将每个组合添加为列表项？

import requests
standings = requests.get('http://games.espn.com/ffl/tools/finalstandings?leagueId=379978&seasonId=2012')

from bs4 import BeautifulSoup
soup = BeautifulSoup(standings.text, 'html.parser')
## Ask BeautifulSoup to find all of the records
pat = soup.find_all('tr', attrs={'class':'sortableRow evenRow'})
teams = []
for x in pat:
name1 = x.find('a').text
record1 = x.find('td', {'class':'sortableREC'}).text
pf1 = x.find('td', {'class':'sortablePF'}).text
pa1 = x.find('td', {'class':'sortablePA'}).text
pfg1 = x.find('td', {'class':'sortablePFG'}).text
pag1 = x.find('td', {'class':'sortablePAG'}).text
diff1 = x.find('td', {'class':'sortableDIFF'}).text

teams.append((name1, record1, pf1, pa1, pfg1, pag1, diff1))

odd =soup.find_all('tr'， attrs={'class'：'sortableRow oddRow'}(

teams2 = []
for team in odd:
name2 = team.find('a').text
record2 = team.find('td', {'class':'sortableREC'}).text
pf2 = team.find('td', {'class':'sortablePF'}).text
pa2 = team.find('td', {'class':'sortablePA'}).text
pfg2 = team.find('td', {'class':'sortablePFG'}).text
pag2 = team.find('td', {'class':'sortablePAG'}).text
diff2 = team.find('td', {'class':'sortableDIFF'}).text
teams2.append((name2, record2, pf2, pa2, pfg2, pag2, diff2))

Answer 1

假设这不仅仅是代码格式错误，这是因为您的.append(...)调用不在循环内。将它们缩进到与变量设置相同的级别(如果在列表创建期间只需要这些值，则不需要(，您应该获得所有相关值。