查询选择的内联用户数据输入操作| Python

Question

我正在用Python开发一个允许用户输入查询的故障排除应用程序。该查询将包含设备的品牌和问题或问题的症状。我正在编写一个脚本，该脚本本质上是对查询进行剖析，以便根据设备的关键字和品牌找到合适的解决方案。

当前代码:#导入模块进口警告

#Define Globals
brands = ["apple", "android", "windows"]
brand = ''
def Main():
    init()
    print("--Welcome to Troubleshooting Applet--")
    print("In your query please include the brand of your device and the problem / symptom of your current issue. n")
    query = input("Enter your query: ").lower()
    brand = set(brands).intersection(query.split())
    if brand != '':
        print(brand)
    else:
        print("Brand in existance not defined")
def init():
    #warnings.filterwarnings("ignore") #Disable while debugging
if __name__ == '__main__':
    Main()

目前，脚本将识别一个品牌，但我不确定如何检查大量的关键字，以便遵循解决方案路线。我希望这个解决方案遵循这样的模式:选择一个品牌，一个特定于该品牌的二级数组，其中包含许多潜在的错误。每个错误都可以定义一个解决方案。

我很感激你的建议，

谢谢,山姆

Answer 1

运行这个我希望这能给你一些想法。您需要修复main():函数的缩进。

#Define Globals
brands = ["apple", "android", "windows"]
brand = ''
import random
def Main():
        init()
        print("--Welcome to Troubleshooting Applet--")
        print("In your query please include the brand of your device and the problem / symptom of your current issue. n")
        query = input("Enter your query: ").lower()
        brand = set(brands).intersection(query.split())
        keywords = ['custom security keywords collection', 'item2', 'key3']
        index = 0
        for i in range(len(query)):
            if query.__contains__(keywords[index]): # __iter__() # could use 'in' keyword here
                #switch/decide
                text = 'run decision'
                print(keywords[index])
            else:
                if len(keywords) < 3:
                    index = index + 1
                text1 = 'continue'
        # OR
        # Test keyword idea...
        tKeyword = random.choice(keywords)
        # You need a lot of work to come up with error decisions right?
        # You may need to start pulling from a Database and checking against large documents?
        # just trying to come up with something to get you going
        print ('RANDOM keyword for TESTING:' + tKeyword)
        if brand != '':
            print(brand)
        else:
            print("Brand in existance not defined")
def init():
        ftp = 0
    #warnings.filterwarnings("ignore") #Disable while debugging
if __name__ == '__main__':
    Main()
    print('ask yourself about escape sequences and encoding for the query? +'
          ' I believe utf-8 is the default encoding for python 3')
def dbconnect():
    url = "http://stackoverflow.com/questions/372885/how-do-i-connect-to-a-mysql-database-in-python"
    url1 = "https://docs.python.org/3/reference/datamodel.html#object.__contains__"
    url2 = "مرحبا I think python is very unicode friendly.."