如何从日志输出中分配特定值



在logstash中,我正在获得此输出,但是,我正在尝试仅从此输出中获取存储库:"用户名/logstashrepo"。请分享您的想法,如何仅 grep 该值并分配给变量。

message: "github_audit: {"actor_ip":"192.168.1.1","from":"repositories#create","actor":"username","repo":"username/logstashrepo","user":"username","created_at":1416299104782,"action":"repo.create","user_id":1033,"repo_id":44744,"actor_id":1033,"data":{"actor_location":{"location":{"lat":null,"lon":null}}}}",
@version: "1",
@timestamp: "2014-11-18T08:25:05.427Z",
host: "15-274-145-63",
type: "syslog",
syslog5424_pri: "190",
timestamp: "Nov 18 00:25:05",
actor_ip: "192.168.1.1",
from: "repositories#create",
actor: "username",
repo: "username/logstashrepo",
user: "username",
created_at: 1416299104782,
action: "repo.create",
user_id: 1033,
repo_id: 44744,
actor_id: 1033,

我在我的配置文件中使用它:

input {
  tcp {
    port => 8088
    type => syslog
  }
  udp {
    port => 8088
    type => syslog
  }
}
filter {
  grok {
    match => [
      "message",
      "%{SYSLOG5424PRI}%{SYSLOGTIMESTAMP:timestamp} %{HOSTNAME:host} %{GREEDYDATA:message}"
    ]
    overwrite => ["host", "message"]
  }
  if [message] =~ /^github_audit: / {
    grok {
      match => ["message", "^github_audit: %{GREEDYDATA:json_payload}"]
    }
    json {
      source => "json_payload"
      remove_field => "json_payload"
    }
  }
}
output {
  elasticsearch { host => localhost }
  stdout { codec => rubydebug }
}

我实际上在这里发布了这个问题,由于某种原因我无法编辑和跟进。

如何从 logstash 输出中 grep particulr 字段

您可以让 json 筛选器将展开的 JSON 对象存储在子字段中。使用突变过滤器将"repo"字段移动到顶层并删除整个子字段。json 过滤器及以后的部分示例:

json {
  source => "json_payload"
  target => "json"
  remove_field => "json_payload"
}
mutate {
  rename => ["[json][repo]", "repo"]
  remove_field => "json"
}

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