要在Rust中使用M:N
线程模型,我需要启动一个池,然后像往常一样开始生成任务。绿色文件给出了以下示例:
#![feature(phase)]
#[phase(plugin)] extern crate green;
green_start!(main)
fn main() {
// Running inside a green pool
// Spawn more green threads?
for x in some_thing.iter() {
spawn(proc() {
some_task()
});
}
}
如果你想动态添加另一个操作系统线程,可以这样做:
extern crate green;
extern crate rustuv;
use std::task::TaskBuilder;
use green::{SchedPool, PoolConfig, GreenTaskBuilder};
let mut config = PoolConfig::new();
// Optional: Set the event loop to be rustuv's to allow I/O to work
config.event_loop_factory = rustuv::event_loop;
let mut pool = SchedPool::new(config);
// Spawn tasks into the pool of schedulers
TaskBuilder::new().green(&mut pool).spawn(proc() {
// this code is running inside the pool of schedulers
spawn(proc() {
// this code is also running inside the same scheduler pool
});
});
// Dynamically add a new scheduler to the scheduler pool. This adds another
// OS thread that green threads can be multiplexed on to.
let mut handle = pool.spawn_sched();
// Pin a task to the spawned scheduler
TaskBuilder::new().green_pinned(&mut pool, &mut handle).spawn(proc() {
/* ... */
});
// Handles keep schedulers alive, so be sure to drop all handles before
// destroying the sched pool
drop(handle);
// Required to shut down this scheduler pool.
// The task will fail if `shutdown` is not called.
pool.shutdown();
有没有办法说使用x数量的操作系统线程,或者它们必须在代码中创建和管理?
根据PoolConfig
的文档,创建新池时可以指定操作系统线程数:
let mut config = PoolConfig::new();
config.threads = 42u;
let mut pool = SchedPool::new(config);
// use your pool with 42 OS threads as you want
config.threads
的默认值由std::rt::default_sched_threads()
提供