可能的重复:
如何创建一个运行STA线程的任务(TPL)?
我正在使用以下代码:
var task = Task.Factory.StartNew<List<NewTwitterStatus>>(
() => GetTweets(securityKeys),
TaskCreationOptions.LongRunning);
Dispatcher.BeginInvoke(DispatcherPriority.Background,
new Action(() =>
{
var result = task.Result; // ERROR!!! The calling thread cannot access this object because a different thread owns it.
RecentTweetList.ItemsSource = result;
Visibility = result.Any() ? Visibility.Visible : Visibility.Hidden;
}));
我遇到了错误:
var result = task.Result; // ERROR!!! The calling thread cannot access this object because a different thread owns it.
我需要做什么来解决此问题?
任务的想法是您可以链接它们:
var task = Task.Factory.StartNew<List<NewTwitterStatus>>(
() => GetTweets(securityKeys),
TaskCreationOptions.LongRunning
)
.ContinueWith(tsk => EndTweets(tsk) );
void EndTweets(Task<List<string>> tsk)
{
var strings = tsk.Result;
// now you have your result, Dispatchar Invoke it to the Main thread
}
您需要将调度程序调用转移到任务继续,看起来像这样:
var task = Task.Factory
.StartNew<List<NewTwitterStatus>>(() => GetTweets(securityKeys), TaskCreationOptions.LongRunning)
.ContinueWith<List<NewTwitterStatus>>(t =>
{
Dispatcher.CurrentDispatcher.BeginInvoke(DispatcherPriority.Background,
new Action(() =>
{
var result = t.Result;
RecentTweetList.ItemsSource = result;
Visibility = result.Any() ? Visibility.Visible : Visibility.Hidden;
}));
},
CancellationToken.None,
TaskContinuationOptions.None);
看起来您正在启动背景任务以开始阅读推文,然后启动另一个任务以读取结果而无需两者之间的任何协调。
我希望您的任务在继续进行中(请参阅http://msdn.microsoft.com/en-us/library/dd537609.aspx),在延续中,您可能需要调用UI线程....
var getTask = Task.Factory.StartNew(...);
var analyseTask = Task.Factory.StartNew<...>(
()=>
Dispatcher.Invoke(RecentTweetList.ItemsSource = getTask.Result));