聚合函数返回 null

Question

>我有这个样本数据

+------+------------+------------+
| CODE | START_DATE | END_DATE   |
+------+------------+------------+
| 0001 | 2012-01-01 | 2012-01-31 |
+------+------------+------------+
| 0001 | 2012-02-01 | 2012-02-29 |
+------+------------+------------+
| 0001 | 2012-03-01 | NULL       |
+------+------------+------------+
| 0002 | 2012-02-01 | 2012-02-29 |
+------+------------+------------+
| 0002 | 2012-03-01 | 2012-03-31 |
+------+------------+------------+
| 0002 | 2012-04-01 | NULL       |
+------+------------+------------+
| 0003 | 2012-02-01 | 2012-02-29 |
+------+------------+------------+
| 0003 | 2012-03-01 | 2012-03-31 |
+------+------------+------------+

DDL

CREATE TABLE SAMPLE
(
    CODE VARCHAR(4),
    START_DATE DATETIME,
    END_DATE DATETIME
)
INSERT INTO SAMPLE (CODE, START_DATE, END_DATE) VALUES ('0001', {d '2012-01-01'}, {d '2012-01-31'})
INSERT INTO SAMPLE (CODE, START_DATE, END_DATE) VALUES ('0001', {d '2012-02-01'}, {d '2012-02-29'})
INSERT INTO SAMPLE (CODE, START_DATE, END_DATE) VALUES ('0001', {d '2012-03-01'}, NULL)
INSERT INTO SAMPLE (CODE, START_DATE, END_DATE) VALUES ('0002', {d '2012-02-01'}, {d '2012-02-29'})
INSERT INTO SAMPLE (CODE, START_DATE, END_DATE) VALUES ('0002', {d '2012-03-01'}, {d '2012-03-31'})
INSERT INTO SAMPLE (CODE, START_DATE, END_DATE) VALUES ('0002', {d '2012-04-01'}, NULL)
INSERT INTO SAMPLE (CODE, START_DATE, END_DATE) VALUES ('0003', {d '2012-02-01'}, {d '2012-02-29'})
INSERT INTO SAMPLE (CODE, START_DATE, END_DATE) VALUES ('0003', {d '2012-03-01'}, {d '2012-03-31'})

我应该得到这些数据

+------+------------+------------+
| CODE | START_DATE | END_DATE   |
+------+------------+------------+
| 0001 | 2012-01-01 | NULL       |
+------+------------+------------+
| 0002 | 2012-02-01 | NULL       |
+------+------------+------------+
| 0003 | 2012-02-01 | 2012-03-31 |
+------+------------+------------+

目前在 SQL Server 2005 中，我使用此查询

SELECT  CODE,
        MIN(START_DATE) AS START_DATE,
        CASE
            WHEN    MAX(ISNULL(END_DATE, {d '9999-12-31'})) = {d '9999-12-31'}
            THEN    NULL
        ELSE
            MAX(END_DATE)
        END AS END_DATE
FROM    SAMPLE
GROUP BY    CODE

我正在作弊 空值 到目前为止 9999-12-31

我正在寻找更好的解决方案

谢谢

Answer 1

您可以利用NULL列和NOT NULL列的COUNT不同的事实。所以脚本可以像这样：

SELECT  CODE,
        MIN(START_DATE) AS START_DATE,
        CASE 
            WHEN    COUNT(*) > COUNT(END_DATE)
            THEN    NULL
        ELSE
            MAX(END_DATE)
        END AS END_DATE
FROM    SAMPLE
GROUP BY    CODE

Answer 2

此脚本使用 cte（公用表表达式）首先获取空end_dates并对其执行左连接。它消除了对您使用的硬编码任意日期的需要。

由于它需要额外的查询，因此它将比初始解决方案慢。

因此，在决定最佳解决方案时，它还取决于记录的数量以及调用此脚本的频率。

;WITH NULL_END_DATES_CTE AS (SELECT CODE FROM SAMPLE WHERE END_DATE IS NULL)
SELECT  S.CODE,
    MIN(S.START_DATE) AS START_DATE,
    CASE WHEN C.CODE IS NULL THEN MAX(S.END_DATE) ELSE NULL END AS END_DATE
FROM    SAMPLE S
LEFT JOIN NULL_END_DATES_CTE C ON C.CODE = S.CODE 
GROUP BY S.CODE,C.CODE
ORDER BY S.CODE