我有一个Arduino激活/停用系统的问题。上传代码的新副本后,我可以获取代码以激活或停用,但是一旦我在上传后激活它并尝试停用安全系统,它只会占2个数字,然后提示我错误。
#include "Keypad.h"
#include "LiquidCrystal.h"
#include "Password.h"
LiquidCrystal lcd(0,1,10,11,12,13);
char newPasswordString; //hold the new password
char newPassword[4]; //character string of newPasswordString
//initialize password to 1234
//you can use password.set(newPassword) to overwrite it
Password password = Password("1234");
byte maxPasswordLength = 6;
byte currentPasswordLength = 0;
// keypad type definition
const byte ROWS = 4; //four rows
const byte COLS = 4; //four columns
char keys[ROWS][COLS] = {
{'1','2','3','A'},
{'4','5','6','B'},
{'7','8','9','C'},
{'*','0','#','D'}
};
byte rowPins[ROWS] = {9,8,7,6}; //Rows 0 to 4
byte colPins[COLS]= {5,4,3,2}; //Columns 0 to 4
int count=0;
Keypad keypad = Keypad( makeKeymap(keys), rowPins, colPins, ROWS, COLS );
void setup()
{
lcd.begin(16, 2);
mainScreen();
}
void loop(){
char key = keypad.getKey();
if (key != NO_KEY){
delay(60);
switch (key){
case 'A': activate(); break;
case 'B': break;
case 'C': break;
case 'D': deactivate(); break;
case '#': break;
case '*': break;
default: processNumberKey(key);
}
}
}
void processNumberKey(char key) {
lcd.print(key);
currentPasswordLength++;
password.append(key);
if (currentPasswordLength == maxPasswordLength) {
activate();
}
}
void activate() {
if (password.evaluate()){
lcd.clear();
lcd.print("Activated.");
delay(1000);
mainScreen();
} else {
lcd.clear();
lcd.print("Wrong Password!");
}
}
void deactivate(){
if (password.evaluate()){
lcd.clear();
lcd.print("Deactivated.");
delay(1000);
mainScreen();
} else {
lcd.clear();
lcd.print("Wrong Password!");
delay(1000);
mainScreen();
}
}
void mainScreen(){
lcd.clear();
lcd.print("Enter Pin:");
keypad.getKey();
}
因此,它首次起作用(激活)和下一次(停用)它没有吗?
currentPasswordLenght
的唯一出现是:
- 全局变量声明和初始化:
byte currentPasswordLength = 0;
-
processNumberKey
中的增量:currentPasswordLength++;
- 在
processNumberKey
中进行比较并调用activate
:if (currentPasswordLength == maxPasswordLength) {
第三个还解释了为什么停用(第二轮)在第二个键按在maxPasswordLength
为 6
之后而失败,而激活后currentPasswordLength
为 4
。
工作代码的示例:
#include <Key.h>
#include <Keypad.h>
#include <Password.h>
const byte ROWS = 4; //four rows
const byte COLS = 4; //four columns
const char keys[ROWS][COLS] = {
{'1','2','3','A'},
{'4','5','6','B'},
{'7','8','9','C'},
{'*','0','#','D'}
};
const byte rowPins[ROWS] = {9,8,7,6};
const byte colPins[COLS] = {5,4,3,2};
Keypad keypad { makeKeymap(keys), rowPins, colPins, ROWS, COLS };
Password passwd { "1234" };
bool activated = false;
byte count = 0;
uint32_t timeout = 0;
void setup() {
Serial.begin(115200);
}
void loop() {
char key = keypad.getKey();
switch (key) {
case '0' ... '9':
Serial.print(key);
passwd << key;
timeout = millis() + 5000;
if (++count == 4) {
Serial.println();
if (passwd.evaluate()) {
activated = !activated;
Serial.println(activated ? F("Activated") : F("Deactivated"));
} else {
Serial.println(F("Wrong password"));
}
passwd.reset();
count = 0;
}
break;
case 'A' ... 'D':
break;
default:
delay(60);
break;
}
if ((count != 0) && (millis() > timeout)) {
Serial.println(F("nTimeout"));
passwd.reset();
count = 0;
}
}