我有一个程序,用户在其中输入一个"地址簿",必须在其中输入5个人才能进行搜索。对于电话号码,它只使用区号来保持快速。
我的问题是,在程序结束时,它要求用户搜索姓名或电子邮件,并返回其所在的索引。我希望它显示此人的实际信息。
static void Main (string[] args)
{
int size = 5;
string[] names = new string[size];
int[] Age = new int[size];
string[] address = new string[size];
int[] phone = new int[size];
string[] email = new string[size];
bool stop = false; // stop to flag for while loops to end loops
string temp;
int counter = 0;
while((stop == false) && (counter <5)) // counter can only get to 5 and both statements must be true
{
Console.WriteLine ("Enter a name or q/Q to quit");
temp = Console.ReadLine ();
if (temp == "q" || temp == "Q") {
Console.WriteLine ("Quitting");
stop = true; // Allowing user to quit
}
else
{
names [counter] = temp; // temp value stored into names array [counter]
}
Console.WriteLine ("Enter the age or q/Q to quit");
temp = Console.ReadLine ();
if (temp == "q" || temp == "Q") {
Console.WriteLine ("Quitting");
stop = true;
}
else
{
Age [counter] = Convert.ToInt16(temp); // converts a string to integer
}
Console.WriteLine ("Enter address or q/Q to quit");
temp = Console.ReadLine ();
if (temp == "q" || temp == "Q") {
Console.WriteLine ("Quitting");
stop = true; // Allowing user to quit
}
else
{
address [counter] = temp;
}
Console.WriteLine ("Enter phone number or q/Q to quit");
temp = Console.ReadLine ();
if (temp == "q" || temp == "Q") {
Console.WriteLine ("Quitting");
stop = true;
}
else
{
phone [counter] = Convert.ToInt32(temp); // converts a string to integer
}
Console.WriteLine ("Enter a email or q/Q to quit");
temp = Console.ReadLine ();
if (temp == "q" || temp == "Q") {
Console.WriteLine ("Quitting");
stop = true; // Allowing user to quit
}
else
{
email [counter] = temp;
counter = counter + 1;
}
}
for (int i = 0; i <5; i++)
{
Console.WriteLine (names [i]);
Console.WriteLine (Age [i]);
Console.WriteLine (address [i]);
Console.WriteLine (phone [i]);
Console.WriteLine (email [i]);
}
Console.WriteLine ("Enter a name or email to search or Q/q to quit");
temp = Console.ReadLine ();
stop = false;
while (stop == false)
{
if (temp == "q" || temp == "Q") {
Console.WriteLine ("Quitting");
stop = true;
}
else
{
for (int i = 0; i <5; i++)
{
if (temp == names [i] || temp == email [i]) {
Console.WriteLine ("Name is found at index {0}", i);
stop = true;
}
else
{
if (i == 5)
{
Console.WriteLine ("Value not found");
stop = true;
}
}
}
}
Console.ReadLine ();
只需更换
Console.WriteLine ("Name is found at index {0}", i);
带有
Console.WriteLine ("Person is found at index {0}. Name: {1}, Age: {2}, Address: {3}, Phone: {4}, Email: {5}", i, names[i], Age[i], address[i], phone[i], email [i]);
你应该把上面的这个方法分解成简短的方法,因为目前它做了很多事情(它有很多责任),很难阅读和理解。第一步可以是将填充数据结构(输入数据)与使用数据结构(打印过滤后的数据)分离开来。
您可以创建一个名为Person
的类,该类的成员为Name、Age、Address、Phone、Email,而不是每个属性都有一个数组,并且只有一个数组-Person
对象的数组。这将简化您的代码。
最好将人员保留在列表中,而不是数组中,因为您事先不知道用户何时会点击Q)uit并停止添加新人员。如果大小为10000,并且用户在输入10个条目后退出,则为Person对象分配了9990个已分配但未使用的空间。
此外,考虑一下当Person的某些字段未输入时如何处理这种情况。(您是想使用例如空字符串,还是根本不想将半填充的实例添加到列表中…).
您应该使用具有名称、年龄、地址、电话号码属性的地址簿类,并且您可以使用通用列表来存储用户输入的数据。
泛型列表已具有查找方法。
更改
if (temp == names [i] || temp == email [i]) {
Console.WriteLine ("Name is found at index {0}", i);
stop = true;
}
至
if (temp == names [i] || temp == email [i]) {
Console.WriteLine (names [i]);
Console.WriteLine (Age [i]);
Console.WriteLine (address [i]);
Console.WriteLine (phone [i]);
Console.WriteLine (email [i]);
}
在用户输入q或q之前,我不会麻烦地停止。