我的目标是遍历对象列表,并在每个列循环方法中显示图像src和name,但没有成功。我已经看过attr("src","image src"(方法,但没有在循环中使用。我也可能在 html 中使用了错误的类......我这样做的方式是否正确?我是jQuery的新手。感谢您的任何帮助。
.HTML:
<div class="container" style="max-width:800px;">
<h2 align="center" id="character-text">Choose your character:</h2>
<div class="row" id="charOptions" style="max-width:800px;" align="center">
<div class="col-lg-3 char-img"></div>
<div class="col-lg-3 char-img"></div>
<div class="col-lg-3 char-img"></div>
<div class="col-lg-3 char-img"></div>
</div>
.JS:
//Objects
var hansolo = {
name: "Han Solo",
attack: 10,
hp: 20,
counter: 0,
src: "assets/images/hansolo.jpg",
}
var chewy = {
name: "Chewy",
attack: 10,
hp: 20,
counter: 0,
src: "assets/images/chewy.jpg",
}
var jabba = {
name: "Jabba",
attack: 10,
hp: 20,
counter: 0,
src: "assets/images/jabba.jpg",
}
var greedo = {
name: "Greedo",
attack: 10,
hp: 20,
counter: 0,
src: "assets/images/greedo.jpg",
}
var choices = [hansolo, chewy, jabba, greedo];
for (var i = 0; i < choices.length; i++) {
var charOptions = $("<charOptions>");
charOptions
.addClass( "char-img char-text")
.attr("src", choices[i].src)
.text(choices[i].name);
$(".charOptions").append(charOptions);
console.log(charOptions);
}
您想遍历对象列表并在每列中显示图像 src 和名称?
首先,删除 HTML 标记中的所有 .col-lg-*,因为我们应该动态创建它。
然后,只需遍历对象并创建要追加的相关 HTML 对象。
var charOptionsRow = $('#charOptions');
$.each(choices, function(index, choice) {
// Create a new div.col-lg-3 to be appended to row.
var charOptionCol = $('<div>')
.addClass('char-option col-lg-3');
// Append image to col.
var charImg = $('<img>')
.addClass('char-img')
.attr('src', choice.src);
charOptionCol.append(charImg);
// Append text to col.
var charText = $('<h5>')
.addClass('char-text')
.text(choice.name);
charOptionCol.append(charText);
// Append column to row.
charOptionsRow.append(charOptionCol);
});
看来您正在尝试创建一个 img 标签
另外img
是一个自闭合标签和一个void元素,你可能无法向其添加text
。我猜你正在寻找alt
房产
for (var i = 0; i < choices.length; i++) { tag
// creating img
var charOptions = $("<img>");
charOptions
.addClass( "char-img char-text")
.attr("src", choices[i].src)
.alt(choices[i].name);
// use id selector since there is no dom with class charOptions
$("#charOptions").append(charOptions);
console.log(charOptions);
}
jquery
//Objects
var hansolo = {
name: "Han Solo",
attack: 10,
hp: 20,
counter: 0,
src: "assets/images/hansolo.jpg",
}
var chewy = {
name: "Chewy",
attack: 10,
hp: 20,
counter: 0,
src: "assets/images/chewy.jpg",
}
var jabba = {
name: "Jabba",
attack: 10,
hp: 20,
counter: 0,
src: "assets/images/jabba.jpg",
}
var greedo = {
name: "Greedo",
attack: 10,
hp: 20,
counter: 0,
src: "assets/images/greedo.jpg",
}
var choices = [hansolo, chewy, jabba, greedo];
$(choices).each(function(){
console.log(this.src);
var div = "<div class='col-lg-3 char-img'><img
src="+this.src+" /></div>"
$('#charOptions').append(div);
});
html
<div class="container" style="max-width:800px;">
<h2 align="center" id="character-text">Choose your character:
</h2>
<div class="row" id="charOptions" style="max-width:800px;" align="center">
<div class="col-lg-3 char-img" style="width:800px; color:red;" >a</div>
<div class="col-lg-3 char-img">b</div>
<div class="col-lg-3 char-img">c</div>
<div class="col-lg-3 char-img">d</div>
</div>
https://jsfiddle.net/sunilsoma/p111hyk3/