来自的联系人包括密件抄送和收件人

Question

我想在联系表单中发送密件抄送电子邮件以及收件人。如何在代码中包含密件抄送？我在下面的代码中没有看到错误，但它不会向您发送电子邮件到密件抄送或收件人。如果我删除密件抄送，它会将您发送给收件人。

$recipient = "[e-mail]";   
// Set the email subject.
$subject = "New contact from $name";
// Build the email content.
$email_content = "Name:  $namen";
$email_content .= "Email:  $emailnn";
$email_content .= "Phone:  $phonenn";
$email_content .= "Message:  $messagen";
$email_content .= "$subscribe: Yesn";
// Build the email headers.
$email_headers = "From: $name <$email>";
$email_headers = "BCC: [e-mail]";
// Send the email.
if (mail($recipient, $subject, $email_content, $email_headers)) {
// Set a 200 (okay) response code.
http_response_code(200);
echo "Thank You for Contacting Us.";
} 

Answer 1

您正在覆盖变量。
如果添加.=它将附加字符串。我想你之间也需要一个逗号换行符。

$email_headers = "From: $name <$email>n";
$email_headers .= "BCC: [e-mail]";