tkinter listbox转到错误的函数

Question

在我的代码中，我必须列出与2个不同函数绑定的框。这是代码：

from tkinter import *
import string
class App:
    def change_dropdown(self, *args):
        print(self.Lb1.curselection())
        self.Lb2.insert(self.count, self.choices[self.Lb1.curselection()[0]])
        self.count+=1
    def delete_dropdown_selected(self, *args):
        print(self.Lb2.curselection())

    def __init__(self, master):
        self.count = 0
        self.left = Frame(master)
        self.left.config()
        self.left.pack(side=LEFT)
        self.choices = []
        self.yscroll = Scrollbar(master, orient=VERTICAL)
        self.Lb1 = Listbox(self.left, selectmode=SINGLE, yscrollcommand=self.yscroll.set, font=50, bd=2)
        self.Lb2 = Listbox(self.left, selectmode=SINGLE, bd=2)
        for j in range(2):
            for i in range(26):
               self.Lb1.insert(i,string.ascii_lowercase[i])
               self.choices.append(string.ascii_letters[i])
        self.Lb1.config(width=50, height=30)
        self.Lb1.pack(side=TOP, fill=BOTH, expand=1)
        self.Lb2.config(font=30, width=50, height=10)
        self.Lb2.pack(side=BOTTOM, fill=BOTH, expand=1, pady=10)
        self.Lb2.bind('<<ListboxSelect>>', self.delete_dropdown_selected)
        self.Lb1.bind('<<ListboxSelect>>', self.change_dropdown)
        self.yscroll.pack(side=LEFT, fill=Y)
        self.yscroll.config(command=self.Lb1.yview)

root = Tk()
root.resizable(width=False, height=False)
app = App(root)
root.mainloop()

问题是，当我单击LB2中的一个项目时，它将转到 thats_dropdown（）而不是 delete_dropdown_selected（）。我不明白为什么，因为我在这里指定它：

self.Lb2.bind('<<ListboxSelect>>', self.delete_dropdown_selected)

Answer 1

在tkinter listbox中使用exportselection=0选项。

self.Lb1 = Listbox(self.left, selectmode=SINGLE, yscrollcommand=self.yscroll.set, font=50, bd=2, exportselection=0)
self.Lb2 = Listbox(self.left, selectmode=SINGLE, bd=2, exportselection=0)

如何在tkinter listbox中突出显示选择？