成员{id,通过,名称,年龄,性别,电子邮件,sysdate}loginlog {id,sys}
我想确保排除所有以前的登录数据
select
to_char(ll.SYS),
mm.ID,
count(*)
from
member mm,
loginlog ll
where
mm.ID=ll.ID
and (
(select
to_char(l.SYS),
m.ID,
count(*)
from member m , loginlog l
where l.ID = m.ID group by(to_char(l.SYS) , m.ID)
) != all(select to_char(ls.SYS), ls.ID ,ls.NUM from loginsave ls)
)
group by(to_char(ll.SYS),mm.ID);
这给出了"
ORA-00913: too many values
00913. 00000 - "too many values"
*Cause:
*Action:
11, 11 column error
这是您要做的吗?
select to_char(ll.SYS), mm.ID, count(*)
from member mm join
loginlog ll
on mm.ID = ll.ID
group by to_char(ll.SYS), mm.ID
having (to_char(ll.SYS), mm.ID, count(*)) not in
(select to_char(ls.SYS), ls.ID, ls.NUM from loginsave ls);