cow = {
"data": [
{
"id": "1179640025492630",
"indicator": "google-analytics|UA-97996598-1",
"type": "API_KEY"
},
{
"id": "1469013519830038",
"indicator": "google-analytics|UA-96613605-2",
"type": "API_KEY"
},
{
"id": "1459958767410551",
"indicator": "google-analytics|UA-86399386-2",
"type": "API_KEY"
},
{
"id": "1507839102569000",
"indicator": "google-analytics|UA-89570367-2",
"type": "API_KEY"
},
{
"id": "1276736575767341",
"indicator": "google-analytics|UA-69774312-4",
"type": "API_KEY"
},
{
"id": "1292251910882451",
"indicator": "google-analytics|UA-93952538-3",
"type": "API_KEY"
}
],
"paging": {
"cursors": {
"after": "NQZDZD",
"before": "MAZDZD"
}
}
}
我想从数据字典中提取" ID":" 1179640025492630"。
我试图将循环使用:
for i in cow['data']:
for key,value in i:
if(i == 'id'):
print key,value
else:
pass
它给我一个值错误,例如:
Traceback (most recent call last):
File "./dict.py", line 14, in <module>
for key,value in ['data']:
ValueError: too many values to unpack
,如果我使用.iteritems
,我会得到AttributeError
:
Traceback (most recent call last):
File "./dict.py", line 14, in <module>
for key,value in ['data'].iteritems:
AttributeError: 'list' object has no attribute 'iteritems'
如果您要做的就是打印与id
S相关的所有值:
for thing in cow["data"]:
print(thing["id"])
输出:
1179640025492630
1469013519830038
1459958767410551
1507839102569000
1276736575767341
1292251910882451
如果要使用嵌套for
循环的清洁液解决方案,则可以使用Python的map
函数在data
中的所有字典上迭代,并且仅使用id
值。
>>> list(map(lambda d: 'id: {}'.format(d['id']), cow['data']))
['id: 1179640025492630', 'id: 1469013519830038', 'id: 1459958767410551', 'id: 1507839102569000', 'id: 1276736575767341', 'id: 1292251910882451']
如果要挖掘 id 字段,请使用映射函数:
map(lambda item: ("id", item["id"]), cow["data"])
您将获得一个元组列表(请注意,PY3地图是懒惰的,您将强制评估列表。
,也可以结合列表和词典理解,这可能更易于沿线处理。
result = [{k:v for k,v in dikt.items() if k == "id"} for dikt in cow['data']]
给你
[{'id':'1179640025492630'},{'id':'1469013519830038'},{'id':'1459958767410551'}1276736575767341'},{'id':'129225191082451'}]
您可以像这样打印出来:
print "n".join([i['id'] for i in result])