我不明白为什么我的缩进是错误的，当我输入答案时，除了错误之外，它不会输出任何内容

Question

我正在使用带有Python 2.7.6的PyScripter运行它。我不明白为什么我的代码是错误的。有人可以给我一个解释吗？

def mainMenu():
answer = input("""Main Menu:
Pythagoras
Repeat Program
Quit""")
if answer == "Pythagoras":
pythagoras()
elif answer == "Repeat Program":
mainMenu()
elif answer == "Quit":
print("Program ended")
else:
mainMenu()
def pythagoras():
if answer == "Pythagoras":
aNotSquared = input("Input the value of A")
bNotSquared = input("Input the value of B")
aSquared = aNotSquared ** 2
bSquared = bNotSquared ** 2
valueC = aSquared + bSquared
print(valueC)

mainMenu()

Answer 1

不确定粘贴时是否发生缩进错误，但在外面，这也是需要修复的几件事

• 在进入pythagoras()函数之前已经测试了if answer == 'Pythagoras'，在函数内部检查answer不起作用也没有意义
• 无法对需要将输入转换为intstrings执行数学运算
• 为清晰起见，在输入和打印结果时进行常规格式
设置
• PEP-8snake_case不CamelCase

略微改进的版本：

from math import sqrt
def main_menu():
answer = input("""Main Menu:
Pythagoras
Repeat Program
QuitnChoose option from above: """)
if answer == "Pythagoras":
pythagoras()
elif answer == "Repeat Program":
main_menu()
elif answer == "Quit":
print("Program ended")
else:
main_menu()
def pythagoras():
a_not_sqr = int(input("Input the value of A: "))
b_not_sqr = int(input("Input the value of B: "))
a_sqr = a_not_sqr ** 2
b_sqr = b_not_sqr ** 2
c_sqr = a_sqr + b_sqr
c_not_sqr = sqrt(c_sqr)
print(f'C Squared  = {c_sqr}')
print(f'C = {round(c_not_sqr, 2)}')
main_menu()

Main Menu:
Pythagoras
Repeat Program
Quit
Choose option from above: Pythagoras
Input the value of A: 10
Input the value of B: 10
C Squared  = 200
C = 14.14