如何使用回归算法预测员工2020年的薪水。
b = (n * Sum(xy( - Sum(x(Sum(y((/(n * Sum(x^2( - Sum(x(^2(。
公式总和表示
a = (Sum(y(/n(-b(Sum(x(/n(
回归公式 ： (y = a + bx(
请帮我使用算法找到2020年的薪水。
using System;
public class Program
{
public static void Main()
{
Console.WriteLine("Employee Salary Prediction for 2020 using Regression Algorithm");
int[,] xyInputs= new int[,]{{2002,1000},{2003,2000},{2004,3000},{2005,4000},{2006,5000},{2007,6000},{2008,7000}
,{2009,8000},{2010,9000},{2011,10000},{2012,11000},{2013,12000},{2015,13000},{2016,14000}
,{2017,15000}};
//consider those values like x and y for the regression formula (y = a + bx;)
int xValueyValue=0;
int xValue=0;
int yValue=0;
int xSquareValue=0;
int lastSalary=0;
for (int i=0;i<xyInputs.Length/2;i++)
{
int temp=0;
for (int j=0;j < xyInputs.Length/2;j++)
{
try{
if(j==0){
temp =xyInputs[i,j];
xValue = xValue + temp;
xSquareValue = xSquareValue + xValue * xValue ;
}
if(j==1){
xValueyValue = xValueyValue + (temp * xyInputs[i,j]);
yValue = yValue + xyInputs[i,j];
temp=0;
}
if(i == ((xyInputs.Length/2)-1)){
lastSalary=(xyInputs[i,j]);
}
}catch(Exception ex){
}
}
}
//Formula Sum represents Sumation of b = (n * Sum(xy) - Sum(x)Sum(y)) / (n * Sum(x^2) - Sum(x)^2).
int b =(xyInputs.Length * ((xValueyValue) - (xValue * yValue)))/((xyInputs.Length * xSquareValue)- (xValue * xValue));
//Formula Sum represents Sumation of a = (Sum(y)/n)-b(Sum(x)/n)
int a = (yValue - (b * xValue))/xyInputs.Length;
Console.WriteLine("Regression y Value for x = 2020 is :" +(lastSalary + (a + (b * 2020))));
}
}