如何在关键的XSLT1.0中传递动态分隔符

Question

如何传递动态分隔符，这里我传递'|'作为静态，当我在xsl中声明变量并使用这个地方时，它会给出错误。

<xsl:variable name="separator" select="'|'"/>
<xsl:key name="key-before" match="result" use="substring-before(Store, $separator)"/>

---

输入XML

<?xml version="1.0" encoding="iso-8859-1"?>
<results>
    <result>
        <Store>0180|1</Store>
    </result>
    <result>
        <Store>0180|2</Store>
    </result>
    <result>
        <Store>0181</Store>
    </result>
    <result>
        <Store>0183</Store>
    </result>
    <result>
        <Store>abc</Store>
    </result>
    <result>
        <Store>def</Store>
    </result>
    <result>
        <Store>0181|2</Store>
    </result>
    <result>
        <Store>0180|3</Store>
    </result>
    <result>
        <Store>0181|1</Store>
    </result>

</results>

XSLT:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
<xsl:output method="xml" indent="yes"/>
<xsl:param  name="key-direction" select="'p'"/>
<xsl:param  name="separator" select="results/sep"/>
<xsl:variable name="demo" select="substring-before(Store,$separator)"/>
<xsl:key name="group-before" match="/results/result" use="substring-before(Store,$demo)" />
<xsl:key name="group-after" match="/results/result" use="substring-before(Store,$demo)" />
<xsl:template match="/results">
        <xsl:choose>
          <xsl:when test="$key-direction='p'">
            <xsl:apply-templates select="result[generate-id() = generate-id(key('group-before', substring-before(Store,$separator))[1])]"/>
          </xsl:when>
          <xsl:otherwise>
            <xsl:apply-templates select="result[generate-id() = generate-id(key('group-after', substring-before(Store,$separator))[1])]"/>
          </xsl:otherwise>
        </xsl:choose>
  </xsl:template>
  <xsl:template match="result">
    <xsl:choose>
          <xsl:when test="$key-direction='p'">
                    <xsl:for-each select="key('group-before', substring-before(Store,$separator))">
                          <xsl:choose>
                          <xsl:when test="contains(Store,'|')">
                                <td>
                                <xsl:value-of select="substring-before(Store,$separator)"/>
                                 <xsl:value-of select="'|'"/>
                                 <xsl:value-of select="position()"/>
                            </td>
                          </xsl:when>
                          <xsl:otherwise>
                           <td><xsl:value-of select="Store"/></td>
                          </xsl:otherwise>
                        </xsl:choose>
                   </xsl:for-each>
          </xsl:when>
          <xsl:otherwise>
            <xsl:for-each select="key('group-after', substring-after(Store,$separator))">
                  <xsl:choose>
                  <xsl:when test="contains(Store,'|')">
                        <td>
                         <xsl:value-of select="substring-after(Store,$separator)"/>
                        <xsl:value-of select="'|'"/>
                         <xsl:value-of select="position()"/>
                    </td>
                  </xsl:when>
                  <xsl:otherwise>
                <td><xsl:value-of select="Store"/></td>
                  </xsl:otherwise>
                </xsl:choose>
           </xsl:for-each>
          </xsl:otherwise>
        </xsl:choose>
  </xsl:template>
</xsl:stylesheet>

Answer 1

您所要求的是不可能的(在XSLT 1.0中)。xsl:key的match和use属性都不能包含对变量的引用