我想直接将文件从HTML表单上载至S3,而不先将其保存到服务器。我正在使用boto3和烧瓶。烧瓶和HTML代码在下面发布。我测试了与S3的连接,因此我的HTML表格必须存在问题。错误说"文件名必须是字符串"。感谢您的帮助。
烧瓶:
.route('/upload', methods=['GET', 'POST'])
@login_required
def upload():
try:
latestfile = request.form.get('filetoupload')
conn = boto3.client('s3', region_name="eu-west-1", endpoint_url="example.com", aws_access_key_id='the access key here', aws_secret_access_key='the secret key here',)
conn.create_bucket(Bucket="mytestbucket22")
bucket_name = "mytestbucket22"
conn.upload_file(latestfile, bucket_name, latestfile)
return render_template('dashboard.html', name=current_user.username, sumsg="Upload done!")
except Exception as ermsg:
print(ermsg)
return render_template('dashboard.html', name=current_user.username, ermsg=ermsg)
html:
<form action="./upload" method="post" enctype="multipart/form-data">
<input name="filetoupload" type="file">
<button type="submit" class="buttonformatting" onclick="showImage();">Download</button></a>
</form>
您需要构建具有签名策略的表格,如下所示:https://docs.aws.amazon.com/amazons3/latest/api/sigv4-post-example.html
您可以使用此烧瓶实用程序为您进行签名生成:https://github.com/fastmonkeys/pontus
从其网站上的示例中进行复制,以生成表单字段值:(取决于您以HTML形式将其放置):
import boto3
from flask import current_app
from pontus import AmazonS3SignedRequest
session = boto3.session.Session(
aws_access_key_id=current_app.config.get('AWS_ACCESS_KEY_ID'),
aws_secret_access_key=current_app.config.get('AWS_SECRET_ACCESS_KEY')
)
bucket = session.resource('s3').Bucket('testbucket')
signed_request = AmazonS3SignedRequest(
key_name=u'my/file.jpg',
mime_type=u'image/jpeg',
bucket=bucket,
session=session
)
signed_request.form_fields
从烧瓶请求获得上传文件后,您可以使用 conn.upload_fileobj()方法上传。现在,您正在使用 conn.upload_file(),该>期望文件名指向磁盘上的文件。
做
之类的事情file = request.files['filefield']
conn.upload_fileobj(file, 'mybucket', 'mykey')
更多文档和信息:
烧瓶请求对象为您提供 fileStorage 对象的行为就像常规python文件:http://flask.pocoo.org/docs/0.12/api/papi/#flask.request.request.files.files.files.filesfiles
在此处阅读boto3文档:https://boto3.readthedocs.io/en/latest/reference/services/s3.html#s3.client.upload_fileobj