我设法为js阵列编写了函数码:
function searchcontacts() {
var input = document.getElementById("myInput");
var btn = document.getElementById("myBtn");
var inputcase = input.value.toUpperCase();
for (i=0; i < contacts.length; i++){
if(contacts[i].name.indexOf(inputcase) != -1) {
contacts[i].showcontact();
}
else {
continue;
document.write("no result found </br>");
}
}
}
function showcontact() {
document.write("Name:"+this.name+"<br>");
document.write("address:"+this.address+"<br>");
document.write("email:"+this.email+"<br>");
document.write("phone number:"+this.phone+"<hr>");
}
function Contact(name,address,email,phone) {
this.name=name;
this.address=address;
this.email=email;
this.phone=phone;
this.showcontact=showcontact;
}
现在,我试图找到一种返回字符串"找不到的结果"的方法,当时什么都没有找到。因为继续;跳过这一步。有人知道我该怎么做吗?新的网络开发!预先感谢您!
您需要跟踪您找到的结果数量,并在循环后检查一下,类似的内容:
function searchcontacts() {
var input = document.getElementById("myInput");
var btn = document.getElementById("myBtn");
var inputcase = input.value.toUpperCase();
var results = 0;
for (i=0; i < contacts.length; i++){
if(contacts[i].name.indexOf(inputcase) != -1) {
contacts[i].showcontact();
results++;
}
}
if(results === 0){
document.write("no result found </br>");
}
}