Symfony 身份验证表单不运行

Question

我有表单类型：

class UserType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
// ->add('email')
->add('username', TextType::class)
->add('password', PasswordType::class)
;
}
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults([
'data_class' => User::class,
]);
}
}

实体用户 ：

class User implements UserInterface
{
/**
* @ORMId()
* @ORMGeneratedValue()
* @ORMColumn(type="integer")
*/
private $id;
/**
* @ORMColumn(type="string", length=255)
* @AssertEmail()
*/
private $email;
/**
* @ORMColumn(type="string", length=255)
* @AssertLength(min=2, minMessage="Nom trop petit")
*/
private $username;
/**
* @ORMColumn(type="string", length=255)
* @AssertLength(min=4, minMessage="Mot de passe trop petit")
*/
private $password;
/**
* @AssertEqualTo(propertyPath="password", message="Le mot de passe ne correspond pas")
*/
public $confirm_password;
public function getId(): ?int
{
return $this->id;
}
public function getEmail(): ?string
{
return $this->email;
}
public function setEmail(string $email): self
{
$this->email = $email;
return $this;
}
public function getUsername(): ?string
{
return $this->username;
}
public function setUsername(string $username): self
{
$this->username = $username;
return $this;
}
public function getPassword(): ?string
{
return $this->password;
}
public function setPassword(string $password): self
{
$this->password = $password;
return $this;
}
/**
* @inheritDoc
*/
public function getRoles()
{
return ["ROLE_USER"];
}
/**
* @inheritDoc
*/
public function getSalt()
{
// TODO: Implement getSalt() method.
}
/**
* @inheritDoc
*/
public function eraseCredentials()
{
// TODO: Implement eraseCredentials() method.
}
}

控制器 ：

/**
* @Route("/login", name="login")
*/
public function login()
{
// the identification is done thanks Symfony security configuration
return $this->render("security/login.html.twig", [
"form" => $this->createForm(UserType::class )->createView()
]);
}

安全防火墙配置文件：

firewalls:
main:
anonymous: lazy
provider: in_database
form_login:
login_path: security_login
check_path: security_login
logout:
path: security_logout
target: home

和观点：

{% extends 'base.html.twig' %}
{% block title %}Hello SecurityController!{% endblock %}
{% block body %}
<h1>Login</h1>
<form action="{{ path('security_login') }}" method="post">
<div class="form-group">
<input type="text" class="form-control" placeholder="Nom" required name="_username">
</div>
<div class="form-group">
<input type="password" class="form-control" placeholder="Mot de passe" required name="_password">
</div>
<div class="form-group">
<button type="submit" class="btn btn-success">Connexion</button>
</div>
</form>
{% endblock %}

使用此代码，将运行识别。

现在，我想在 Twig 文件中使用 Twig 表单标签，如下所示：

{{ form_start(form) }}
{{ form_row(form.username, {"attr": {"placeholder": "Nom", "name": "_username", "required": "required"}, "label": "Nom" }) }}
{{ form_row(form.password, {"attr": {"placeholder": "Mot de passe", "name": "_password", "required": "required"}, "label": "Mot de passe" }) }}
<button type="submit" class="btn btn-success">Valider</button>
{{ form_end(form) }}

但是当我使用此代码时，我收到错误消息：

键"_username"必须是给定的字符串"NULL"。

通常，我的表单可以正常运行。为什么在这里，表单不起作用？

谢谢你的回答。

Answer 1

我认为您忘记在控制器中处理表单请求，为此您需要将SymfonyComponentHttpFoundationRequest参数注入login()方法，下面的示例：

public function login(Request $request)
{
$form->handleRequest($request);
if (true === $form->isSubmitted() && true === $form->isValid()) {
// stuff
}
}

同样在防火墙中，请编辑form_login，路由路径不正确，因为在控制器注释中您指定了name="login"：

form_login:
login_path: login
check_path: login

Answer 2

您的身份验证逻辑不好。按照此文档... https://symfony.com/doc/current/security/form_login_setup.html