从ScrollView返回NSArray中的位置

Question

我试图创建一个可点击UIImageView的数组的滚动视图。我的目标是当一个ImageView被点击时，它返回它在数组中占据的位置。问题是我不知道如何"抓住"这个职位的号码。我怎么做呢?

到目前为止，我有:

- (IBAction)respondToTapGesture:(UITapGestureRecognizer *)recognizer {
    NSLog(@"%@",)//here is where i want to return the element's position.
}
-(void) preenchemenu {
    [menu setContentSize:CGSizeMake(400, 91)];
    int x=0;
    imagensmenu=[NSArray arrayWithObjects:[UIImage imageNamed:@"teste2.tiff"],[UIImage    imageNamed:@"teste2.tiff"], nil];
    for (int i = 0; i <3; i++) {
        UIImageView *imageView = [[UIImageView alloc] initWithFrame:CGRectMake(x,0 , 90, 91)];
        x=x+90;
        imageView.image = [imagensmenu objectAtIndex:i];
        imageView.tag = 1000+ i;
        imageView.userInteractionEnabled = YES;
        imageView.multipleTouchEnabled = YES;
        UITapGestureRecognizer *tapRecognizermenu = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(respondToTapGesture:)];
        tapRecognizermenu.numberOfTapsRequired = 1;
        [imageView addGestureRecognizer:tapRecognizermenu];
        [menu addSubview:imageView];
    }
}

Answer 1

你可以创建一个数组来保存你的imageView，然后当它被点击时找到你的imageView在这个数组中的位置。

为

添加一个属性

@property (nonatomic, strong) NSMutableArray *imageViews;

在init

中初始化

- (id)init...
{
  self = [super init...
  if (self) {
    _imageViews = [NSMutableArray array];
  }
  return self;
}

然后稍微修改当前方法，将imageViews添加到该数组以及菜单的子视图

[self.imageViews addObject:imageView];
[menu addSubview:imageView];

然后在你的手势识别器回叫中你可以做

- (void)respondToTapGesture:(id)sender;
{
  UIView *view = [sender view];
  NSLog(@"%d", [self.imageViews indexOfObject:view]);
}

Answer 2

按

查找索引

- (IBAction)respondToTapGesture:(UITapGestureRecognizer *)recognizer
{
  UIView *view = recognizer.view;
  NSLog(@"Index of image in array is %d", view.tag-1000);
}