Google_Service_Exception错误500未捕获

Question

我正在使用google api客户端获取博客帖子列表(见下面的代码)。

try {
        // create service and get data
        $blogger = new Google_Service_Blogger($this->client);
        // https://developers.google.com/blogger/docs/3.0/reference/posts/list
        // GET https://www.googleapis.com/blogger/v3/blogs/blogId/posts
        if ($this->cache->contains('posts')) {
            $posts = $this->cache->fetch('posts');
        }
        else {
            $posts = $blogger->posts->listPosts($this->bloggerId, $optParams);
            $this->cache->save('posts', $posts, 600); // 600 = 10 mins
        }
        return $posts;

        } catch (apiServiceException $e) {
        // Error from the API.
        //print 'There was an API error : ' . $e->getCode() . ' : ' . $e->getMessage();
    } catch (Exception $e) {
        //print 'There was a general error : ' . $e->getMessage();
    }

这在大多数情况下工作得很好，但偶尔我会得到一个未捕获的API错误。

Google_Service_Exception: Error calling GET https://www.googleapis.com/blogger/v3/blogs/8894809254783984374/posts?maxResults=5: (500) Backend Error at /var/www/releases/20140607051057/vendor/google/apiclient/src/Google/Http/REST.php:79)"} []

有谁知道为什么会抛出这个错误，我该如何处理它?

欢呼

Answer 1

问题出在名称空间上。你可以使用泛型:

} catch (Exception $e) {
    //print 'There was a general error : ' . $e->getMessage();
}

或者更具体的:

try {
  ...
} catch (Google_Service_Exception $e) {
  //print 'There was a general error : ' . $e->getMessage();
}

Exception是所有Exception的基类。见http://php.net/manual/en/class.exception.php