>我编写了一个脚本来将文件复制到"所有用户"桌面或"公共桌面"
但是,我们有一个混合环境。有些人正在使用Windows XP,有些人正在使用Windows 7。
$SOURCE = "I:PathToFolder*"
$DESTINATION7 = "c$UsersPublicDesktop"
$DESTINATIONXP = "c$Documents and SettingsAll UsersDesktop"
$computerlist = Get-Content I:PathToFilecomputer-list.csv
$results = @()
$filenotthere = @()
$filesremoved = @()
foreach ($computer in $computerlist) {
if((Test-Connection -Cn $computer -BufferSize 16 -Count 1 -ea 0 -quiet))
{
Write-Host "\$computer$DESTINATION"
Copy-Item $SOURCE "\$computer$DESTINATION" -Recurse -force
} else {
$details = @{
Date = get-date
ComputerName = $Computer
Destination = $Destination
}
$results += New-Object PSObject -Property $details
$results | export-csv -Path I:PathTologsoffline.txt -NoTypeInformation -Append
}
}
DESTINATION 为空。扩展基思的建议:
foreach ($computer in $computerlist) {
if((Test-Connection -Cn $computer -BufferSize 16 -Count 1 -ea 0 -quiet))
{
$OS = Get-WmiObject -Computer $computer -Class Win32_OperatingSystem
if($OS.caption -like '*Windows 7*'){
$DESTINATION = $DESTINATION7
}
if($OS.caption -like '*Windows XP*'){
$DESTINATION = $DESTINATIONXP
}
}
}
这也可以避免您遇到的错误。 empty $DESTINATION
.
在 foreach $computerlist循环中,可以使用 WMI 获取每台计算机的操作系统标题:
$OS = Get-WmiObject -Computer $computer -Class Win32_OperatingSystem
然后检查$OS
if($OS.caption -like '*Windows 7*'){
#Code here for Windows 7
}
#....
我有一个稍微不同的目标...但是感谢您的基本知识。
del C:scriptsOS.csv
$computerlist = Get-Content c:scriptscomputerlist.csv
foreach ($computer in $computerlist) {
if((Test-Connection -Cn $computer -BufferSize 16 -Count 1 -ea 0 -quiet))
{
Get-WMIObject Win32_OperatingSystem -ComputerName $computer |
select-object CSName, Caption, CSDVersion, OSType, LastBootUpTime, ProductType| export-csv -Path C:ScriptsOS.csv -NoTypeInformation -Append
}
}