我想通过将 show_password_field
作为true在 AddUserType.php
中的可选值中作为true来重复使用表单字段。我的编辑表单字段不应包含密码字段。所以我已经使用了这个
if ($options['show_password_field']) {
$builder->add('password','password',array('required'=>true));
}
形式类型。有人可以弄清楚吗?树枝文件的第37行中的问题是什么。
属性"密码"也不是一种方法"密码()", " getPassword()"/" ISPassword()"或" __call()"存在并拥有公共 在类" Symfony Component form formView"类中访问 sokoSimueditorBundle:用户:adduser.html.twig在第37行。
addusertype.php
namespace SokosimuEditorBundleFormType;
use SymfonyComponentFormAbstractType;
use SymfonyComponentFormFormBuilderInterface;
use SymfonyComponentFormExtensionCoreTypeSubmitType;
use SymfonyComponentOptionsResolverOptionsResolverInterface;
class AddUserType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add('alias','text',array('required'=>false));
$builder->add('email', 'email',array('required'=>false));
if ($options['show_password_field']) {
$builder->add('password','password',array('required'=>true));
}
$builder->add('mobile','text',array('required'=>false));
$builder->add('submit', 'submit');
}
public function setDefaultOptions(OptionsResolverInterface $resolver)
{
$resolver->setDefaults(array(
'data_class' => 'SokosimuUserBundleEntityUser',
'show_password_field' => true
));
}
/**
* Returns the name of this type.
*
* @return string The name of this type
*/
public function getName()
{
return 'adduser';
}
}
和第37行adduser.html.twig
<div class="form-group">
<label for="password">Password:</label>
{{ form_widget(form.password,{'attr':{'class':'form-row'}}) }}
{{ form_errors(form.password) }}
</div>
渲染编辑的控制器
public function editEditorUserAction(User $user,Request $request){
$form = $this->createForm(new AddUserType(),$user,array(
'show_password_field' => false));
$form->handleRequest($request);
if($form ->isValid() && $form->isSubmitted()){
$em = $this->get('doctrine')->getManager();
$editUser = $user ->getEditoruser();
$em->persist($editUser);
$em->flush();
return $this->redirect($this->generateUrl('sokosimu_editor_userlist'));
}
return $this->render('SokosimuEditorBundle:User:addUser.html.twig', array(
'form' => $form->createView(),
'user' => $user->getId()
));
}
您必须检查form.password是否存在。
{% if form.password is defined %}
<div class="form-group">
<label for="password">Password:</label>
{{ form_widget(form.password,{'attr':{'class':'form-row'}}) }}
{{ form_errors(form.password) }}
</div>
{% endif %}