Firebase 导入排序后的数据

Question

我想从 Firebase 数据库中导入排序后的数据。

举个例子：我有一家小公司，我需要导入所有雇主的数据。我owner_01这意味着我必须导入其子owner_uid owner_01匹配的所有用户。

这些数据将在网站上使用，这意味着我将使用javascript。

这里有 JSON ：

    {
  "Owner_users" : {
    "owner_01" : {
      "email" : "[e-mail]",
      "uid" : 123
    },
    "owner_02" : {
      "email" : "[e-mail]",
      "uid" : 12345
    }
  },
  "Users" : {
    "user_01" : {
      "Email" : "[e-mail]",
      "Name" : "asd",
      "age" : 23,
      "owner_uid" : 123,
      "uid" : "asd"
    },
    "user_02" : {
      "Email" : "[e-mail]",
      "Name" : "all",
      "age" : 49,
      "owner_uid" : 123,
      "uid" : "asdfg"
    },
    "user_03" : {
      "age" : 60,
      "email" : "[e-mail]",
      "owner_uid" : 12345,
      "uid" : "sdfzsvsvsd"
    }
  }
}

检查此 URL 以查看数据库的结构。更新：

网页代码：

<table class="mdl-data-table mdl-js-data-table ">
    <thead>
      <tr>
        <th class="mdl-data-table__cell--non-numeric">Email</th>
        <th>Age</th>
        <th>uid</th>
      </tr>
    </thead>
    <tbody id="usersData">
    </tbody>
  </table>

JS代码

var usersRef = firebase.database().ref('Users')
var query = usersRef.orderByChild('owner_uid').equalTo('123');
query.on("child_added", function(snapshot) {
  var email = snap.child("Email").val;
  var name = snap.child("Name").val;
  var uid = snap.child("uid").val;
  $("#usersData").append("<tr><td" + email + "</td><td>" + name + "</td><td>" + uid + "</td></tr>");
});

Answer 1

var usersRef = firebase.database().ref('Users')
var query = usersRef.orderByChild('owner_uid').equalTo('YOUR UID HERE');
query.on("child_added", function(snapshot) {
  console.log(snapshot.val().uid);
});