如何在java中每行输出几个数字

Question

嗨，我是编程新手，所以请不要嘲笑我愚蠢的问题。

我编写的程序要求用户输入一个数字，而程序应该输出从0到输入数字的所有数字(无论是正数还是负数(。我已经尝试了3个不同版本的

这是我的代码：

int min = Integer.MIN_VALUE;
int max = Integer.MAX_VALUE;
int num = PutiL.validNum(min, max, "number");
//this my utility methode which check if number is in range and if it is not a double or letter
int i = 0, z;
int y = 0;
//3rd version
while (i <= num) {
    for (z = 0; z < 4; z++) {
        System.out.print(i + " ");
        i++;
    }
    System.out.println();
}
//2nd version
if (num > 0) {
    for (i = 0; i <= num; y++) {
        for (z = 0; z < 4; z++) {
           System.out.print(i + ",");
            i++;
        }
        System.out.println();
    }
} else {
    for (i = 0; i > num; y--) {
        for (z = 0; z < 4; z++) {
           System.out.print(i + ",");
            i--;
        }
        System.out.println();
    }
}
//1st version`enter code here`
if (num > 0) {
    for (i = 0; i <= num; i++)
    {
       System.out.print(i + ",");
    }
} else {
    for (i = 0; i >= num; i--) {
        System.out.print(i + ",");
    }
}
System.out.println();

问题是代码不会在用户输入数字后立即停止。有人能给我一个提示吗，因为我没有更多的想法了。

这是PutiL方法

public static int validNum(int min, int max, String words) {
    int num;
    do {
        System.out.println("Please enter " + words);
        while (!kb.hasNextInt()) {
            System.out.println("Please re-enter ");
            kb.nextLine();
        }
        num = kb.nextInt();
        if (num < min || num > max) {
            System.out.println("Not in range - re-entertproper range is "
                    + min + " - " + max);
        }
    } while (num < min || num > max);
    return num;
}

Answer 1

//2nd version
if (num > 0)
{
    for (i = 0; i <= num; y++)  <== THIS MAKE INFINITE too, OKAY.. ^^, change i to stop
    {
        for (z = 0; z < 4; z++)
        {
           System.out.print(i + ",");
            i++;
        }
        System.out.println();
    }
} else
{
    for (i = 0; i > num; y--) <== THIS MAKE INFINITE LOOPS, OKAY.. ^^, it must i to stop
    {
        for (z = 0; z < 4; z++)
        {
           System.out.print(i + ",");
            i--;
        }
        System.out.println();
    }
}

如果答案正确，别忘了接受。^^

Answer 2

public static void main(String[] args) {
    int number = Integer.parseInt(args[0]);
    if (number >= 0) {
        for (int i = 0; i <= number; i++) {
            System.out.println(i);
        }
    } else {
        for (int i = 0; i >= number; i--) {
            System.out.println(i);
        }
    }
}

或者更简洁一点，复制println语句。。。

public static void main(String[] args) {
    int number = Integer.parseInt(args[0]);
    int increment = number >= 0 ? 1 : -1;
    for (int i = 0; i != number + increment; i += increment) {
        System.out.println(i);
    }
}

Answer 3

这将为用户提供一个对话框，用户输入的值将为零。

首次导入：

import javax.swing.JOptionPane.*;

然后：

int user_choice = Integer.parseInt(
showInputDialog(null, "Please enter a number."));
if(user_choice > 0){
  for(int temp = 0; temp <= user_choice; temp++){
  System.out.println(temp);    
  }
}
else{
  for(int temp = 0; temp >= user_choice; temp--){
  System.out.println(temp);    
  }
}

Answer 4

"程序应该输出从0到输入数字的所有数字"one_answers"我希望他们在一行中打印例如4，然后跳到另一行">

if(num >=0) {
  for (z = 0; z <= num; z++)
  {
    System.out.print(z + " ");
    if(z > 0 && z%4==0)
      System.out.println();
  }
}
else {
  // similar loop for negatives
}
System.out.println();

Answer 5

感谢大家的帮助我解决了这个问题，我自己真的很容易，这是我使用的代码，现在它的工作非常完美

for(i = 0; i <= num; i++)
        {
            System.out.print(i + " ");
            y++;
            if(y % 4 == 0)
            {
                System.out.println();
            }
        }
        for(i = 0; i >= num; i--)
        {
            System.out.print(i + " ");
            y++;
            if(y % 4 == 0)
            {
                System.out.println();
            }
        }

但再次感谢大家提出我的想法。