用户提供程序构造函数第二个参数

Question

我有一个简单的自定义UserProvider

class UserProvider extends EntityRepository implements UserProviderInterface
{
public function loadUserByUsername($username)
{
    $q = $this
        ->createQueryBuilder('u')
        ->where('u.username = :username OR u.email = :email')
        ->setParameter('username', $username)
        ->setParameter('email', $username)
        ->getQuery();
    try {
        $user = $q->getSingleResult();
    } catch (NoResultException $e) {
        $message = sprintf(
            'Unable to find an active admin EntUserBundle:User object identified by "%s".',
            $username
        );
        throw new UsernameNotFoundException($message, 0, $e);
    }
    return $user;
}
public function refreshUser(UserInterface $user)
{
    $class = get_class($user);
    if (!$this->supportsClass($class)) {
        throw new UnsupportedUserException(
            sprintf(
                'Instances of "%s" are not supported.',
                $class
            )
        );
    }
    return $this->find($user->getId());
}
public function supportsClass($class)
{
    return $this->getEntityName() === $class
        || is_subclass_of($class, $this->getEntityName());
}
}

和相应的服务

ent.user_provider:
    class: EntUserBundleEntityUserProvider
    arguments:
        em: "@doctrine"

我有这个错误

ContextErrorException: Catchable Fatal Error: Argument 2 passed to DoctrineORMEntityRepository::__construct() must be an instance of DoctrineORMMappingClassMetadata, none given

我知道Symfony API需要2个参数，第二个是MappingClassMetadata，但我到底应该给什么作为服务的参数?

提前致谢

Answer 1

1. 在UserProvider类中创建构造:

   use SymfonyComponentSecurityCoreUserUserProviderInterface;
   use DoctrineORMEntityManager;
   ...
   class UserProvider implements UserProviderInterface
   {
       protected $em;
       public function __construct(EntityManager $em)
       {
          $this->em = $em;
       }
      public function loadUserByUsername($username)
      {
         $q = $this->em->getRepository('AcmeDemoBundleEntityUser')->createQueryBuilder('u')
             ->where('u.username = :username OR u.email = :email')
             ->setParameter('username', $username)
             ->setParameter('email', $username)
             ->getQuery();
       ....
      }
      // other methods required by UserProviderInterface
   }
   

2. 服务。yml:

   ent.user_provider:
       class: EntUserBundleEntityUserProvider
       arguments: ["@doctrine.orm.default_entity_manager"]
   

在Symfony 2.5中测试过。