我想从一组C#对象生成以下XML:
<?xml version="1.0" encoding="utf-16"?>
<MyRoot xmlns="http://sample.com">
<Things>
<This>
<ThisRef>this ref</ThisRef>
</This>
<That>
<ThatRef>that ref</ThatRef>
</That>
</Things>
</MyRoot>
不幸的是,XML节点Things可以包含几个This或That节点,并且我无法控制XML模式。我需要创建能够编写正确XML的C#对象,但我在Things集合方面遇到了问题。
到目前为止,我拥有的是:
[XmlRoot("MyRoot", Namespace = XmlNamespace)]
public class MyRoot
{
public const string XmlNamespace = "http://sample.com";
public List<MyThing> Things { get; set; }
}
[XmlInclude(typeof(This))]
[XmlInclude(typeof(That))]
public class MyThing
{
}
[XmlRoot(Namespace = MyRoot.XmlNamespace)]
[XmlType("This")]
public class This : MyThing
{
public string ThisRef { get; set; }
}
[XmlRoot(Namespace = MyRoot.XmlNamespace)]
[XmlType("That")]
public class That : MyThing
{
public string ThatRef { get; set; }
}
[TestClass]
public class so
{
[TestMethod]
public void SerializeTest()
{
// Create object to serialize
var data = new MyRoot { Things = new List<MyThing>() };
data.Things.Add(new This { ThisRef = "this ref" });
data.Things.Add(new That { ThatRef = "that ref" });
// Create XML namespace
var xmlNamespaces = new XmlSerializerNamespaces();
xmlNamespaces.Add(string.Empty, MyRoot.XmlNamespace);
// Write XML
var serializer = new XmlSerializer(typeof(MyRoot));
using (var writer = new StringWriter())
{
serializer.Serialize(writer, data, xmlNamespaces);
var xml = writer.ToString();
Console.WriteLine(xml);
}
}
}
生成以下XML:
<?xml version="1.0" encoding="utf-16"?>
<MyRoot xmlns="http://sample.com">
<Things>
<MyThing d3p1:type="This" xmlns:d3p1="http://www.w3.org/2001/XMLSchema-instance">
<ThisRef>this ref</ThisRef>
</MyThing>
<MyThing d3p1:type="That" xmlns:d3p1="http://www.w3.org/2001/XMLSchema-instance">
<ThatRef>that ref</ThatRef>
</MyThing>
</Things>
</MyRoot>
所以,我有两个问题:
- 如何让XmlSerializer写入This和That节点,而不是MyThing的节点
- 如何阻止XmlSerializer向This和That节点(当前写为MyThing)添加其他命名空间信息
发布到stackoverflow是什么让你立即找到答案?我只需要做以下事情:
[XmlRoot("MyRoot", Namespace = XmlNamespace)]
public class MyRoot
{
public const string XmlNamespace = "http://sample.com";
[XmlArrayItem(Type = typeof(This))]
[XmlArrayItem(Type = typeof(That))]
public List<MyThing> Things { get; set; }
}
public class MyThing
{
}
public class This : MyThing
{
public string ThisRef { get; set; }
}
public class That : MyThing
{
public string ThatRef { get; set; }
}