如何将BMI计算添加到以下代码中

Question

下面是我的代码：

def inForm():
  name = requestString("What is your name?")
  age = requestInteger("What is your age?")
  height = requestInteger("What is your height?")
  weight = requestInteger("What is your weight?")
  print "Hello", name, "!", "You are", age,"years old!", "Your height  
  is", height, "cm", "and you weigh", weight, "kg"

我需要将BMI计算添加到此代码中，这是我的公式，BMI=体重/（身高*身高）

根据BMI显示这些信息：

你的体重严重不足15

你的体重严重不足，从15.0到16.0

你的体重从16.0减到18.5

你的体重在18.5到25 之间是正常的

你超重25到30

你是中度肥胖30至35

你从35岁到40岁严重肥胖

你是非常严重的肥胖超过40

我似乎想不通，我该怎么办？

提前感谢！

Answer 1

为什么不使用requestNumber来表示身高和体重呢。此外，打印声明可以像我下面演示的那样更短。另外，我使用%s%d%r这被称为字符串格式化操作。

def inForm():
 name = requestString("Please enter your name")
 age = requestInteger("How old are you?")
 height = requestNumber("How tall are you? (Meters)")
 weight = requestNumber("How heavy are you? (Kilograms)")
 bmi = weight/(height*height)
 print "Hello, %s! I see that you are %r years old, %r meters tall, weight %r kgs and your BMI is %d." % (name, age, height, weight, bmi)
 n = bmi
 if n<15:
  print "You are very severely underweight"
 elif 15<=n<=16:
  print "You are severely underweight"
 elif 16<n<=18.5:
  print "You are underweight"
 elif 18.5<n<=25:
  print "Your weight is normal"
 elif 25<n<=30:
  print "You are overweight"
 elif 30<n<=35:
  print "You are moderately obese"
 elif 35<n<=40:
  print "You are severely obese"
 elif n>40:
  print "You are very severely obese"

Answer 2

计算bmi时，通常使用身高单位为米（而不是厘米）。这意味着您需要对公式中从cm到m的转换进行两次调整：

bmi = 10000 * weight / (height*height)
print bmi

你可以使用if elif--文本部分的else语句：

if bmi < 15:
    message = "very severely underweight"
elif bmi <= 16:
    message = "severely underweight"
# Add more elif parts here...
else:
    message = "very severely obese"
print "You are", message