误差时，删除序列化的JSON数组

Question

我正在尝试对json字符串进行挑选。

这是我的代码：

[System.Serializable]
public class SharedWorlds
{
    public int worldId { get; set; }
    public System.DateTime uploaded { get; set; }
    public string username { get; set; }
    public string levelName { get; set; }
    public string gameVersion { get; set; }
    public string description { get; set; }
    public string filename { get; set; }
    public string screenshot1 { get; set; }
    public string screenshot2 { get; set; }
    public string userTag { get; set; }
    public string userURL { get; set; }
    public double price { get; set; }
    public int    nrDownload { get; set; }
    public int    votes { get; set; }
}
[System.Serializable]
public class Record {
    public List<SharedWorlds> record;
}
    try {
        SDE3D _webService = new SDE3D();
        result= _webService.GetMassiveWorldsList ();
        var records = JsonUtility.FromJson<Record>(result);
    }
    catch(System.Exception ex) {
        Debug.Log (ex.Message.ToString ());
    }

这是我有效的JSON(这里有两个记录，但我想每次发送许多记录(。

[
  {
    "worldId": 5,
    "uploaded": "/Date(1524875719000)/",
    "username": "quik",
    "levelName": "Station",
    "gameVersion": "1.0.1",
    "description": "iwoeijksf",
    "filename": "0000003.dat",
    "screenshot1": "0000003a.png",
    "screenshot2": "0000003b.png",
    "userTag": "",
    "userURL": "",
    "price": 0,
    "nrDownload": 5,
    "votes": 5
  },
  {
    "worldId": 4,
    "uploaded": "/Date(1524875659000)/",
    "username": "aksio",
    "levelName": "Garage",
    "gameVersion": "1.0.1",
    "description": "Adlkld",
    "filename": "0000003.dat",
    "screenshot1": "0000003a.png",
    "screenshot2": "0000003b.png",
    "userTag": "",
    "userURL": "",
    "price": 0,
    "nrDownload": 4,
    "votes": 4
  }  
]

我遇到了错误：

"参数exception：json必须代表对象类型。"

我很确定错误在此代码行中：

var records = JsonUtility.FromJson<Record>(result);

如何对JSON对象的数组进行序列化？

谢谢

Answer 1

，因为您的JSON数据不是Record。这是SharedWorld s的集合。这样的东西：

var sharedWorlds = JsonUtility.FromJson<SharedWorld[]>(result);

或也许：

var sharedWorlds = JsonUtility.FromJson<List<SharedWorld>>(result);

您可以创建Record：

var record = new Record { record = sharedWorlds };

如果JSON需要在Record中进行估算，则需要以Record对象的格式：

{
    "record": 
    [
        /* the rest of your JSON within the square brackets */
    ]
}

然后是Record：

var record = JsonUtility.FromJson<Record>(result);

---

*旁注：您的类和可变名称以及所使用的复数化确实令人困惑。其语义可能不会使您的调试更容易为您带来。

Answer 2

您可以进入json