无法读取其他应用程序共享的文件Uri，即Whatsapp

Question

当文件通过文件提供程序由其他应用程序共享时，我的应用程序中收到的 Uri 不可读。如果我尝试获取文件路径或从中创建文件，则它说文件不存在。示例 Uri 来自 whatsapp 是 content://com.whatsapp.provider.media/item/91836 .当我尝试从 Uri 读取位图时，它会给出安全异常。

代码行打开创建方法：

Uri mediaUri = getIntent().getParcelableExtra(Intent.EXTRA_STREAM);
Bitmap bitmap = MediaStore.Images.Media.getBitmap(getContentResolver(), mediaUri);

清单：

<activity
        android:name=".ui.main.MainActivity"
        android:screenOrientation="portrait"
        android:windowSoftInputMode="adjustNothing">
        <intent-filter>
            <action android:name="android.intent.action.SEND" />
            <category android:name="android.intent.category.DEFAULT" />
            <data android:mimeType="image/*" />
            <data android:mimeType="video/mp4" />
            <!--<data android:mimeType="video/*" />-->
        </intent-filter>
    </activity>

例外：

Caused by: java.lang.SecurityException: Permission Denial: opening provider com.whatsapp.MediaProvider from ProcessRecord{fbda37f 23891:com.fayvo/u0a273} (pid=23891, uid=10273) that is not exported from UID 10133
        at android.os.Parcel.createException(Parcel.java:1953)
        at android.os.Parcel.readException(Parcel.java:1921)
        at android.os.Parcel.readException(Parcel.java:1871)
        at android.app.IActivityManager$Stub$Proxy.getContentProvider(IActivityManager.java:4159)
        at android.app.ActivityThread.acquireProvider(ActivityThread.java:6759)
        at android.app.ContextImpl$ApplicationContentResolver.acquireUnstableProvider(ContextImpl.java:2912)
        at android.content.ContentResolver.acquireUnstableProvider(ContentResolver.java:1879)
        at android.content.ContentResolver.openTypedAssetFileDescriptor(ContentResolver.java:1460)
        at android.content.ContentResolver.openAssetFileDescriptor(ContentResolver.java:1313)
        at android.content.ContentResolver.openInputStream(ContentResolver.java:1033)
        at android.provider.MediaStore$Images$Media.getBitmap(MediaStore.java:919)

Answer 1

在这些情况下使用此方法对我有用：

private File readSharedContentUri(Uri contentUri) {
    // Get content resolver.
    ContentResolver contentResolver = getContentResolver();
    File targetFile = null;
    try {
        InputStream inputStream = contentResolver.openInputStream(contentUri);
        byte[] buffer = new byte[inputStream.available()];
        inputStream.read(buffer);
        targetFile = PathUtil.getFilePath(context, true, "received_media_" + System.currentTimeMillis(), CommonUtils.isMimeTypeOfImage(contentResolver.getType(contentUri)) ? ".jpg" : ".mp4");
        inputStream.close();
        OutputStream outStream = new FileOutputStream(targetFile);
        outStream.write(buffer);
        outStream.close();
    } catch (Exception e) {
        e.printStackTrace();
    }
    return targetFile;
}