离子2中的分组和总和JSON阵列

Question

我的json看起来像

[ 
{t_id :"1",  val1 : "1" ,   title:"cash to purchase",   unit :"bag"},
{t_id :"1"  ,val1 : "1" ,  title:"cash to purchase", unit :"bag"}
{t_id :"1",val1 : "1" , title:"cash to purchase", unit :"bag"}
{t_id :"2",val1 : "4" , title:"offload", unit :"bag"},
{t_id :"2",val1 : "5" , title:"onroad", unit :"bag"},
{t_id :"3", val1 : "5" , title:"Onroad", unit :"bag"},
{t_id :"3", val1 : "6" , title:"Onroad", unit :"bag"},
]

我想按T_ID进行分组，并根据每个T_ID找到Val1的总和。

标题：购买现金

包：3

标题：卸载

包：9

标题：Onroad

包：11

Answer 1

您去这里。端到端完整解决方案：

var array = [{t_id:"1",val1:"1",title:"cash to purchase",unit:"bag"},{t_id:"1",val1:"1",title:"cash to purchase",unit:"bag"},{t_id:"1",val1:"1",title:"cash to purchase",unit:"bag"},{t_id:"2",val1:"4",title:"offload",unit:"bag"},{t_id:"2",val1:"5",title:"onroad",unit:"bag"},{t_id:"3",val1:"5",title:"Onroad",unit:"bag"},{t_id:"3",val1:"6",title:"Onroad",unit:"bag"}];
var grouped = [];
array.forEach(function(o) {
  if (!this[o.t_id]) {
    this[o.t_id] = {
      t_id: o.t_id,
      val1: 0,
      title: o.title
    };
    grouped.push(this[o.t_id]);
  }
  this[o.t_id].val1 += Number(o.val1);
}, Object.create(null));
console.log(grouped);
$scope.results = grouped;

将下面的代码复制到您的html：

<ion-content>
  <ion-list>
    <ion-item class="" ng-repeat="result in results">
        <div class="item item-text-wrap">
          Title: {{result.title}}
          <br>
          Bag: {{result.val1}}
        </div>
    </ion-item>
  </ion-list>
</ion-content>

Answer 2

制作一个新对象，以存储所有value W.R.T t_id的总和为

var groupObj = {};
list.forEach( ele => 
    groupObj[ele.t_id] = groupObj[ele.t_id] ? 
          {title: ele.title, sum: groupObj[ele.t_id].sum + Number(ele.val1)} :
          {title: ele.title, sum: Number(ele.val1) }
);

这将使groupObj作为

{
    1: { title: "cash to purchase", sum: 3 },
    2: { title: "onroad", sum: 9 },
    3: { title: "Onroad", sum: 11 }
}

如果您需要进一步的帮助，请添加注释。