我正在使用popper.js在使用类.js-share-cf-btn
单击元素时显示具有 .js-share-cf-popover
类的弹出式弹出式Elment。
,但我希望弹出窗口仅在单击外面时关闭。在这里,我显示弹出窗口的实际代码:
var reference = $('.js-share-cf-btn');
var popover = $('.js-share-cf-popover');
popover.hide();
$(document).on('click', reference, function(e) {
e.preventDefault();
popover.show();
var popper = new Popper(reference, popover, {
placement: 'top',
});
});
我在这里找到了一些东西,但我无法做到它
在这里我的JSFIDDLE
您可以通过删除事件委托并在事件上检查目标,然后使用.is(((如果e.target等于引用按钮,否则hide(来实现这一目标弹出式(
请参阅小提琴
添加摘要作为您的代码:
还在Popper
实例中进行了更改,您应该通过当前单击js-share-cf-btn
,因此$(e.target)
元素
$(function() {
var reference = $('.js-share-cf-btn');
var popover = $('.js-share-cf-popover');
popover.hide();
$(document).on('click touchend', function(e) {
var target = $(e.target);
// ne need to reshow and recreate popper when click over popup so return;
if(target.is(popover)) return;
if (target.is(reference)) {
e.preventDefault();
popover.show();
var popper = new Popper(target, popover, {
placement: 'top',
});
}else {
popover.hide();
}
});
});
body {
background: #20262E;
padding: 20px;
font-family: Helvetica;
}
.section {
background: #fff;
padding: 20px;
font-size: 25px;
text-align: center;
transition: all 0.2s;
margin: 0 auto;
width: 300px;
margin-bottom: 20px;
}
.share-popover {
background: red;
color: white;
padding: 10px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.12.9/umd/popper.min.js" integrity="sha384-ApNbgh9B+Y1QKtv3Rn7W3mgPxhU9K/ScQsAP7hUibX39j7fakFPskvXusvfa0b4Q" crossorigin="anonymous"></script>
<div class="section">
<p>Section 1</p>
<a href="#" class="js-share-cf-btn">This is the trigger</a>
</div>
<div class="section">
<p>Section 2</p>
<a href="#" class="js-share-cf-btn">This is the trigger</a>
</div>
<div class="section">
<p>Section 3</p>
<a href="#" class="js-share-cf-btn">This is the trigger</a>
</div>
<div class="share-popover js-share-cf-popover">
This is the popup
</div>
这样的事情应该可以做到(通过单击某个地方时检查目标(:
$(function() {
var ref = $('.js-share-cf-btn');
var popover = $('.js-share-cf-popover');
popover.hide();
$(document).on('click', function(e) {
var target = $(e.target);
if (target.is(ref) || target.is(popover) ) {
e.preventDefault();
popover.show();
var popper = new Popper(ref, popover, {
placement: 'right',
});
}else {
popover.hide();
}
});
});
https://jsfiddle.net/e8al9tje/
对于那些使用React的人,我创建了一个事件的要点,您可以将其连接到任何组件时,在单击外面时将其关闭:
https://gist.github.com/elie222/850bc4adede996508aba2090cd5da1
我找到了一个非常简单的解决方案。
jQuery版本
<div class="Popper">
<div class="stopPropagation">
<p>Clicking on me won't close the Popper</p>
</div>
</div>
$('.stopPropagation').on('click touchend', function(e) {
e.stopPropagation()
})
由于点击事件不会传播到Popper,因此单击时不会关闭Popper。
React版本
<Popper>
{/* eslint-disable-next-line jsx-a11y/click-events-have-key-events */}
<div onClick={e => e.stopPropagation()} role="none">
<p>Clicking on me won't close the Popper</p>
</div>
</Popper>