PHP 致命错误:调用未定义的函数 pdo_query()

Question

在谷歌和堆栈溢出上找不到答案 代码如下

<?php
pdo_query("CREATE TABLE IF NOT EXISTS `ims_cyl_vip_video` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT, 
`uniacid` int(5) NOT NULL,
`title` varchar(255) NOT NULL,
`uid` varchar(25) NOT NULL,
`openid` varchar(255) NOT NULL,
`time` varchar(15) NOT NULL,
`video_url` text NOT NULL,
`share` int(3) NOT NULL,
`yvideo_url` text NOT NULL,
`type` VARCHAR(25) NOT NULL,
`index` int(2) NOT NULL,
`video_id` int(11) NOT NULL,
UNIQUE KEY `id` (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=1 ;
CREATE TABLE IF NOT EXISTS `ims_cyl_vip_video_member` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`uniacid` int(10) NOT NULL,
`openid` varchar(255) NOT NULL,
`uid` varchar(25) NOT NULL,
`nickname` varchar(255) NOT NULL,
`avatar` varchar(1000) NOT NULL,
`end_time` varchar(15) NOT NULL,
`is_pay` int(2) NOT NULL,

Answer 1

我认为您正在尝试使用 PHP 创建一个表。下面是可以从中创建表的简单代码示例： 将示例查询替换为 SQL 查询。

<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
} 
// sql to create table
$sql = "CREATE TABLE MyGuests (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY, 
firstname VARCHAR(30) NOT NULL,
lastname VARCHAR(30) NOT NULL,
email VARCHAR(50),
reg_date TIMESTAMP
)";
if ($conn->query($sql) === TRUE) {
echo "Table MyGuests created successfully";
} else {
echo "Error creating table: " . $conn->error;
}
$conn->close();
?>