我正在尝试编写一个密码查询,在该查询中,我记录了一个人的立方体的所有时间。查询工作正常,但我看到的是,如果结果(时间(-[:RECORDED_ON]-(立方体(中没有任何关系,那么我在集合中得到了 1 条记录,两个值均为 null。另外,我想在时代集合DESC中订购日期
这是我的密码:
MATCH(a:App{name:'AllAboutCubes'})<-[:MEMBER_OF]-(p:Cuber) WHERE id(p) = 1234
MATCH(p)<-[:BELONGS_TO {is_active:1}]-(c:Cube)
OPTIONAL MATCH (c)-[:TYPE]->(ct:CubeType)
OPTIONAL MATCH (c)<-[:RECORDED_ON]-(t:Time)-[:RECORDED]-(p)
WITH c,ct,COLLECT({time:t.time,date:t.date}) as times
RETURN c.name as name, c.manufacturer as manufacturer, ct.type as type, id(c) as cube_id, times as times
ORDER BY manufacturer ASC
但我回来了:
"name" "manufacturer" "type" "cube_id" "times"
"Weipo" "MoYu" "2x2" 7452 [{"time":null,"date":null}]
"GTS3M" "MoYu" "3x3" 7453 [{"time":null,"date":null}]
"MoYu Skewb" "MoYu" "Skewb" 7458 [{"time":"12.435","date":1553880809832}]
"WuQue" "QiYi MoFangGe" "4x4" 7459 [{"time":null,"date":null}]
"Valk 3" "QiYi MoFangGe" "3x3" 7454 [{"time":null,"date":null}]
"Mini Rose Valk 3" "QiYi MoFangGe" "3x3" 7456 [{"time":null,"date":null}]
"Valk 2" "QiYi MoFangGe" "2x2" 7450 [{"time":null,"date":null}]
"ChuWen M" "Supernova" "2x2" 7484 [{"time":null,"date":null}]
"Wingy" "X-Man Designs" "Skewb" 7457 [{"time":"12.255","date":1553881012244},{"time":"13.49","date":1553212800000}]
"Bell" "X-Man Designs" "Pyraminx" 7478 [{"time":"9.234","date":1553817600000}]
"Ruipo" "YJ" "2x2" 7451 [{"time":null,"date":null}]
"Little Magic" "YuXin" "3x3" 7455 [{"time":null,"date":null}]
我不想要 [{"时间":空,"日期":空}]
有什么想法吗?谢谢,让我知道!
这应该按降序对日期进行排序,如果没有日期,则返回[]
times
:
MATCH (a:App{name:'AllAboutCubes'})<-[:MEMBER_OF]-(p:Cuber) WHERE id(p) = 1234
MATCH (p)<-[:BELONGS_TO {is_active:1}]-(c:Cube)
OPTIONAL MATCH (c)<-[:RECORDED_ON]-(t:Time)-[:RECORDED]-(p)
WITH c, t ORDER BY t.date DESC
OPTIONAL MATCH (c)-[:TYPE]->(ct:CubeType)
WITH c, ct, CASE WHEN t IS NULL THEN [] ELSE COLLECT({time:t.time,date:t.date}) END as times
RETURN c.name as name, c.manufacturer as manufacturer, ct.type as type, id(c) as cube_id, times
ORDER BY manufacturer