我需要能够在VB或C＃中理想地解析以下字符串，如果不是VB - 我尝试了许多在线找到但无法工作的方法 - 是否有人可以快速工作示例代码可以帮助我吗？
我尝试使用json.net/newtonsoft，但没有任何地方 - 有点生锈！
Dim json As String = "[{""posX"":36,""posY"":74,""data"":{""type"":""A""},""html"":""A""},{""posX"":243,""posY"":77,""data"":{""type"":""A""},""html"":""A""},{""posX"":32,""posY"":279,""data"":{""type"":""B""},""html"":""B""},{""posX"":242,""posY"":285,""data"":{""type"":""c""},""html"":""c""}]"
我感兴趣的值是POSX，POSY和HTML
预先感谢
json.net是正确的方法。也许这可以帮助您。
Dim json As String = "{'position':[{""posX"":36,""posY"":74,""data"":{""type"":""A""},""html"":""A""},{""posX"":243,""posY"":77,""data"":{""type"":""A""},""html"":""A""},{""posX"":32,""posY"":279,""data"":{""type"":""B""},""html"":""B""},{""posX"":242,""posY"":285,""data"":{""type"":""c""},""html"":""c""}]}"
Dim result = JsonConvert.DeserializeObject(json)
Console.WriteLine(result("position")(0)("posX") & " - " & result("position")(0)("posY") & " - " & result("position")(0)("html"))
输出应为
36-74- a
...尚未测试它，但我希望它能使您在正确的轨道上。