我想制作一些不兼容赋值的整数类型,如下所示。
typealias Fatty = Int
typealias Skinny = Int
var a : Fatty = 6
var b: Skinny = 4
a = b // This should throw a compile time error saying the types are incompatible
a = Fatty(b) // this should work
有没有办法在 swift 中做到这一点(无需创建类/结构(?曾经能够在帕斯卡中做到这一点。
是的,您可以定义自己的整数类型,但这并不容易:
public struct Fatty: ExpressibleByIntegerLiteral, Hashable {
public typealias IntegerLiteralType = Int
let value: Int
public init(_ value: Int) {
self.value = value
}
public init(_ skinny: Skinny) {
self.value = skinny.value
}
public init(integerLiteral value: Int) {
self.value = value
}
}
public struct Skinny: ExpressibleByIntegerLiteral, Hashable {
public typealias IntegerLiteralType = Int
let value: Int
public init(_ value: Int) {
self.value = value
}
public init(_ fatty: Fatty) {
self.value = fatty.value
}
public init(integerLiteral value: Int) {
self.value = value
}
}
如果希望类型的行为类似于实整数,则可以使它们符合BinaryInteger
(或其他整数协议(。
可以使用协议以某种方式推广:
public protocol CustomInt: ExpressibleByIntegerLiteral, Hashable, Comparable {
associatedtype ValueType = _ExpressibleByBuiltinIntegerLiteral
var value: ValueType { get set }
init(value: ValueType)
}
extension CustomInt {
public init(integerLiteral value: ValueType) {
self.init(value: value)
}
public init<T: CustomInt>(_ customInt: T) where Self.ValueType == T.ValueType {
self.init(value: customInt.value)
}
}
extension CustomInt where ValueType: Comparable {
public static func < (lhs: Self, rhs: Self) -> Bool {
return lhs.value < rhs.value
}
}
public struct Fatty: CustomInt {
public var value: Int
public init(value: Int) {
self.value = value
}
}
public struct Skinny: CustomInt {
public var value: Int
public init(value: Int) {
self.value = value
}
}