在给定文件扩展名的目录中计数文件

Question

我想在Inno Setup中以给定的文件扩展名计数目录中的文件。我写了下面的代码:

问候,

function AmountOfFilesInDir(const DirName, Extension: String): Integer;
var
  FilesFound: Integer;
  ShouldBeCountedUppercase, ShouldBeCountedLowercase: Boolean;
  FindRec: TFindRec;
begin
  FilesFound := 0;
  if FindFirst(DirName, FindRec) then begin
    try
      repeat
        if (StringChangeEx(FindRec.Name, Lowercase(Extension), Lowercase(Extension), True) = 0) then
          ShouldBeCountedLowercase := False
        else
          ShouldBeCountedLowercase := True;
        if (StringChangeEx(FindRec.Name, Uppercase(Extension), Uppercase(Extension), True) = 0) then
          ShouldBeCountedUppercase := False
        else
          ShouldBeCountedUppercase := True;
        if (FindRec.Attributes and FILE_ATTRIBUTE_DIRECTORY = 0)
           and ((ShouldBeCountedUppercase = True) or (ShouldBeCountedLowercase = True)) then begin
          FilesFound := FilesFound + 1;
        end;
      until not FindNext(FindRec);
    finally
      FindClose(FindRec);
    end;
  end;
  Result := FilesFound;
end;

用法可以是:

Log(IntToStr(AmountOfFilesInDir(ExpandConstant('{sys}*'), '.exe')));

我喜欢减少这个函数代码中的行数，使它看起来更专业，因为它看起来有点长。我需要知道如何在不失败的情况下做到这一点。

Answer 1

FindFirst函数可自行根据通配符(扩展名)选择文件:

function AmountOfFiles(PathWithMask: string): Integer;
var
  FindRec: TFindRec;
begin
  Result := 0;
  if FindFirst(PathWithMask, FindRec) then
  begin
    try
      repeat
        Inc(Result);
      until not FindNext(FindRec);
    finally
      FindClose(FindRec);
    end;
  end;
end;

使用方式:

Log(IntToStr(AmountOfFiles(ExpandConstant('{sys}*.exe'))));