我在一个文件夹中保存了一组RGBA图像,我的目标是将这些图像转换为pgm格式的另一个文件夹,下面是代码:
path1 = file/path/where/image/are/stored
path2 = file/path/where/pgm/images/will/be/saved
list = os.listdir(path1)
for file in listing:
#Transforms an RGBA with channel into an RGB only
image_rgb = Image.open(file).convert('RGB')
#Color separation stains to detect microscopic cells
ihc_hed = rgb2hed(image_rgb)
#Trasnforms the image into a numpy array of the UINT8 Type
cv_img = ihc_hed.astype(np.uint8)
# create color boundaries boundaries detecting black and blue stains
lower = np.array([0,0,0], dtype = "uint8")
upper = np.array([0,0,255], dtype = "uint8")
#calculates the pixel within the specified boundaries and create a mask
mask = cv2.inRange(cv_img, lower, upper)
img = Image.fromarray(mask,'L')
img.save(path2+file,'pgm')
但是我收到一个错误,指出KeyError:"PGM",似乎"pgm"格式不在模式中
感谢您的建议:)
据我所知,scikit image使用Python Imaging Library插件来保存图像文件。太平船务不支持PGM。
请参阅 http://effbot.org/imagingbook/decoder.htm 了解如何为 PIL 编写自己的文件解码器。
提取:
import Image, ImageFile
import string
class SpamImageFile(ImageFile.ImageFile):
format = "SPAM"
format_description = "Spam raster image"
def _open(self):
# check header
header = self.fp.read(128)
if header[:4] != "SPAM":
raise SyntaxError, "not a SPAM file"
header = string.split(header)
# size in pixels (width, height)
self.size = int(header[1]), int(header[2])
# mode setting
bits = int(header[3])
if bits == 1:
self.mode = "1"
elif bits == 8:
self.mode = "L"
elif bits == 24:
self.mode = "RGB"
else:
raise SyntaxError, "unknown number of bits"
# data descriptor
self.tile = [
("raw", (0, 0) + self.size, 128, (self.mode, 0, 1))
]
Image.register_open("SPAM", SpamImageFile)
Image.register_extension("SPAM", ".spam")
Image.register_extension("SPAM", ".spa") # dos version