backbutton确认退出应用程序android+phonegap+jquery

Question

如何在Phonegap在线系统中使用jQuery Mobile在Android中处理物理后退按钮？我想显示确认退出应用程序（是-否）。我试了很多方法，但都没用。

Answer 1

试试这个：

document.addEventListener("deviceready", onDeviceReady, false);
function onDeviceReady() {
    document.addEventListener("backbutton", onBackKeyDown, false); //Listen to the User clicking on the back button
}
function onBackKeyDown(e) {
    e.preventDefault();
    navigator.notification.confirm("Are you sure you want to exit ?", onConfirm, "Confirmation", "Yes,No"); 
    // Prompt the user with the choice
}
function onConfirm(button) {
    if(button==2){//If User selected No, then we just do nothing
        return;
    }else{
        navigator.app.exitApp();// Otherwise we quit the app.
    }
}

Answer 2

第一次单击设置exitApp=true时，第二次单击后退按钮将退出应用程序。但是设置一个Interval将exitApp的状态更改为false。因此，当在1秒内单击两次后退按钮时，将退出应用程序。

document.addEventListener('deviceready', function() {
    var exitApp = false, intval = setInterval(function (){exitApp = false;}, 1000);
    document.addEventListener("backbutton", function (e){
        e.preventDefault();
        if (exitApp) {
            clearInterval(intval) 
            (navigator.app && navigator.app.exitApp()) || (device && device.exitApp())
        }
        else {
            exitApp = true
            history.back(1);
        } 
    }, false);
}, false);

Answer 3

//设备就绪功能

document.addEventListener('deviceready', function() {
    document.addEventListener("backbutton", ShowExitDialog, false);
}, false);

//按下后退按钮时的对话框

 function ShowExitDialog() {
        navigator.notification.confirm(
                ("Do you want to Exit?"), // message
                alertexit, // callback
                'My APp', // title
                'YES,NO' // buttonName
        );
    }

//呼叫退出功能

 function alertexit(button){
        if(button=="1" || button==1)
        {
            device.exitApp();
        }
}

Answer 4

不确定phonegap是否发生了变化，但Suhas和geet的解决方案几乎对我有效。（但肯定给了我使其工作所需的东西，谢谢！）后退按钮基本上坏了。

以下是使它对我有效的调整：

一旦你的应用程序加载，请执行以下操作：

        document.addEventListener("backbutton", onBackKeyDown, false);//hijack the backbutton
        function onBackKeyDown(e){
            var page = $.mobile.activePage.attr('id');
            xStat.rec("back button clicked from page:" + page);
            if (page == 'menuPage'){//are you on the 'root page' from which phonegap will exit?
                e.preventDefault();
                $.mobile.changePage('#aboutToExitAppPage');
            } else {
                window.history.back();//restore normal back button functionality
            }
        }

//somewhere else in your code for the "aboutToExit app" page
        $('#aboutToExitAppPage').on('pageinit', function(){
            $(this).find('#exitApp').on('click', function(){
                navigator.app.exitApp();//quit the app.
            });
        });

和HTML

<div data-role="page" id="aboutToExitAppPage">
    <div data-role="header" id="" data-position="inline" data-backbtn="true" >
        <h1 class=>About to exit app</h1>
    </div>
    <div data-role="content" style="width:100%; height:100%; padding:0;">
        <ul id="" data-role="listview" data-inset="true" data-theme="c" data-dividertheme="b" data-role="fieldContain">
            <input id="exitApp" class="" type="button" value="Exit" data-theme="">
            <a href="#menuPage" data-role='button'>Main Menu</a>
        </ul>
    </div>
</div>

Answer 5

如果用户单击"是"，则退出应用程序。首先通过运行cordova plugin add cordova-plugin-dialogs 安装对话框插件

document.addEventListener("deviceready", onDeviceReady, false);
function onDeviceReady() {
    document.addEventListener("backbutton", onBackKeyDown, false); //Listen to the User clicking on the back button
}
function onBackKeyDown(e) {
    e.preventDefault();
    navigator.notification.confirm("Are you sure you want to exit ?", onConfirm, "Confirmation", "Yes,No"); 
    // Prompt the user with the choice
}
function onConfirm(button) {
    if(button==1){//If User selected Yes, then exit app
        navigator.app.exitApp();
    } else {
        return;
    }
}

Answer 6

试试这个：

// When Device ready
document.addEventListener('deviceready', function() {
    document.addEventListener("clickBackbutton", ExitDialogPrompt, false);
}, false); 
function ExitDialogPrompt() {
    navigator.notification.confirm(
        ("Do you want to Exit?"), // message
        prompt, // callback
        'Your title', // title
        'YES,NO' // button Name
    );
}
function alertexit(button){
    if (button=="0" || button==1) {
       navigator.app.exitApp();
    }
}

Answer 7

这对我有效。

<script type="text/javascript" src="cordova.js"></script>
<script type="text/javascript" src="js/index.js"></script>

使用此

<script type="text/javascript">
    document.addEventListener("deviceready", onDeviceReady, false);
        function onDeviceReady(){
            document.addEventListener("backbutton", function(e) {
                e.preventDefault();
                        if(confirm("Exit App?")) {
                            navigator.app.exitApp();
                        }
            }, false);
        }
    </script>

或

<script type="text/javascript">
document.addEventListener("deviceready", onDeviceReady, false);
    function onDeviceReady(){
        document.addEventListener("backbutton", function(e) {
            e.preventDefault();
            press = press + 1;
            if(press == 1) {
                alert('Press again to exit');
            }
            if(press == 2) {
                navigator.app.exitApp();
            }
        }, false);
    }
</script>