C语言 将令牌存储到数组中，以便稍后作为参数传递

Question

我有一个已经标记的文件，但是我需要将每个标记存储在一个数组中，以便以后用作参数。我该怎么做呢?

//         Read in File           //
FILE *fp;
char buffer[100];
fp = fopen(params, "r");
printf("Here is filename...");
printf("%sn", params);
fseek(fp, 0, SEEK_END);
//byte_size = ftell(fp);
rewind(fp);
if (fgets(buffer,sizeof(buffer),fp) != NULL)
{
    char*p, *b;
    b = buffer;
    printf("parsing %s", buffer);
    while ((p = strsep(&b, ",")) != NULL)
    {
        printf("param: %sn",p);
    }
}
fclose(fp);

Answer 1

使用链表并稍后将其转换为数组可能是好的，因为我们不知道有多少令牌。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char *strsep(char **stringp, const char *delim);
typedef struct node_tag {
    char *str;
    struct node_tag* next;
} list_node;
list_node* create_node(const char *str) {
    list_node* n = malloc(sizeof(list_node));
    if (n == NULL) exit(1);
    if (str == NULL) {
        n->str = NULL;
    } else {
        n->str = malloc(sizeof(char) * (strlen(str) + 1));
        if (n->str == NULL) exit(1);
        strcpy(n->str, str);
    }
    n->next = NULL;
    return n;
}
int main(void) {
    const char *params = "dummy";
    FILE *fp;
    char buffer[100];
    list_node *head = NULL;
    list_node **tail = &head;
    unsigned int count = 0;
    unsigned int i;
    char **array;
    fp = stdin;//fopen(params, "r");
    printf("Here is filename...");
    printf("%sn", params);
    fseek(fp, 0, SEEK_END);
    //byte_size = ftell(fp);
    rewind(fp);
    if (fgets(buffer,sizeof(buffer),fp) != NULL)
    {
        char*p, *b;
        b = buffer;
        printf("parsing %s", buffer);
        while ((p = strsep(&b, ",")) != NULL)
        {
            printf("param: %sn",p);
            *tail = create_node(p);
            tail = &(*tail)->next;
            count++;
        }

    }
    array = malloc(sizeof(char*) * count);
    if (array == NULL) return 1;
    for (i = 0; i < count && head != NULL; i++) {
        list_node *next = head->next;
        array[i] = head->str;
        // Don't free(head->str) because it is used
        free(head);
        head = next;
    }
    for (i = 0; i < count; i++) {
        printf("array[%u] = %sn", i, array[i]);
    }
    for (i = 0; i < count; i++) free(array[i]);
    free(array);
    //fclose(fp);
    return 0;
}

Answer 2

如果您知道令牌的数量，则可以简单地使用array。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char *strsep(char **stringp, const char *delim);
#define ARRAY_SIZE 8
int main(void) {
    const char *params = "dummy";
    FILE *fp;
    char buffer[100];
    char *array[ARRAY_SIZE];
    int array_count = 0;
    int i;
    fp = stdin;//fopen(params, "r");
    printf("Here is filename...");
    printf("%sn", params);
    fseek(fp, 0, SEEK_END);
    //byte_size = ftell(fp);
    rewind(fp);
    if (fgets(buffer,sizeof(buffer),fp) != NULL)
    {
        char*p, *b;
        b = buffer;
        printf("parsing %s", buffer);
        while ((p = strsep(&b, ",")) != NULL)
        {
            printf("param: %sn",p);
            if (array_count < ARRAY_SIZE)
            {
                array[array_count] = malloc(sizeof(char) * (strlen(p) + 1));
                strcpy(array[array_count], p);
                array_count++;
            }
        }

    }
    for (i = 0; i < array_count; i++) {
        printf("array[%u] = %sn", i, array[i]);
    }
    for (i = 0; i < array_count; i++) free(array[i]);
    //fclose(fp);
    return 0;
}