org.json.JSONException: No value for price

Question

我得到结果json和解析在android。org.json.JSONException: No value for price

W/System.err: org.json.JSONException: No value for price
W/System.err:     at org.json.JSONObject.get(JSONObject.java:389)
W/System.err:     at org.json.JSONObject.getString(JSONObject.java:550)

My java class

JSONParser jsonParser = new JSONParser();
// tracks JSONArray
JSONArray albums = null;
// Album id
String album_id = null;
String song_id = null;
String album_name, song_name, price;
// single song JSON url
// GET parameters album, song
private static final String URL_SONG = "my url";

// ALL JSON node names
private static final String TAG_NAME = "name";
private static final String TAG_PRICE = "price";
private static final String TAG_ALBUM = "name";     // album
...
try {
       JSONObject jObj = new JSONObject(json);
       if(jObj != null){
            song_name = jObj.getString(TAG_NAME);
            album_name = jObj.getString(TAG_ALBUM);
            price = jObj.getString(TAG_PRICE);
       }
 } 
 catch (JSONException e) {
        e.printStackTrace();
 }

My json URL:

{
  "id": "551"
  "name": "Rent Disk"
  "price": "3233333"
  "album_id": "3"
  "album": "Michael"
}

如何修复这个异常?非常感谢!!

Answer 1

你可以在value

之前加上这样的检查符

JSONObject jObj = new JSONObject(json);
if(jObj != null) {
    if(jObj.has(TAG_NAME)) {
        song_name = jObj.getString(TAG_NAME);
    }
    if(jObj.has(TAG_ALBUM)){
        album_name = jObj.getString(TAG_ALBUM);
    }
    if(jObj.has(TAG_PRICE)){
        price = jObj.getString(TAG_PRICE);
    }
}

Answer 2

JSONException

抛出表示JSON API有问题

供参考

 {
  "id": "551"
  "name": "Rent Disk"
  "price": "3233333"
  "album_id": "3"
  "album": "Michael"
}

上传Json Here

如果上面是你的json，那么是无效的。

对于您的需求，您应该使用JSONObject .has("") and .isNull("")方法。

你的完美Json是

{ "id": 551, "name": "Cho thue xe Toyota5", "price": "3233333", "album_id": "3", "album": "Huyndai" }

试试这个

 JSONObject myJson = new JSONObject(json);
 String getName = myJson.optString("name");
 int getID= myJson.optInt("id");