进行查询。
我正在寻找一种方法,从电话号码或名称中获得服务内部收藏列表中的联系人,这并不重要。有人能帮我一下吗?
使用与此代码相关的任何代码都不重要
我在developer.android.com找到了这样的东西(IN_VISIBLE_GROUP)。在我的情况下如何使用这个变量?
case (PICK_CONTACT):
if (resultCode == Activity.RESULT_OK) {
Uri contactData = data.getData();
Cursor c = managedQuery(contactData, null, null, null, null);
ContentResolver cr = getContentResolver();
if (c.moveToFirst()) {
String name = c.getString(c.getColumnIndexOrThrow(People.NAME));
String id =c.getString(c.getColumnIndexOrThrow(People._ID));
Cursor phones = cr.query(Phone.CONTENT_URI, null,
Phone.CONTACT_ID + " = " + id, null, null);
}
假设您正在按姓名搜索联系人。如果您想获得所有可能的联系人的favorite值,请在给定的代码中删除selection参数。
//首先从显示名中获取联系人ID:-
String displayName = "Albert Einstein";
Uri contacts = ContactsContract.Contacts.CONTENT_URI;
cur = cr.query(contacts, null, ContactsContract.Contacts.DISPLAY_NAME +"="+displayName,null, null);
int contactIdIndex = cur.getColumnIndex(ContactsContract.PhoneLookup._ID);
int contactId = cur.getInt(contactIdIndex);
//Make a query to get the Starred value:-
Cursor starred = cr.query(ContactsContract.Contacts.CONTENT_URI,
new String[] { ContactsContract.Contacts.STARRED },
ContactsContract.Contacts._ID + " = " + contactId,
null, null);
if (starred != null && starred.moveToFirst())
{
int fav = starred.getInt(0);
}
if (starred != null)
starred.close();
}
您可以删除获取联系人ID然后查询星号值的步骤,直接根据显示名称
像这样?
final private static class DataQuery {
public static final int COLUMN_MIMETYPE = 1;
public static final int COLUMN_PHONE = 2;
public static final int COLUMN_RAWCONTACT_ID = 3;
public static final int COLUMN_PHONE_NUMBER = COLUMN_DATA1;
public static final String[] PROJECTION = new String[] { Data._ID, Data.MIMETYPE, Data.DATA1, Data.RAW_CONTACT_ID };
public static final String SELECTION_PHONE = Data.DATA1 + "=?";
}
long findContact(Context context, String number) {
long rawContactId = -1;
final Cursor cursor = context.getContentResolver().query(Data.CONTENT_URI, DataQuery.PROJECTION, DataQuery.SELECTION_PHONE, new String[] { number }, null);
try {
if (cursor.moveToFirst()) {
rawContactId = cursor.getLong(DataQuery.COLUMN_RAWCONTACT_ID);
}
} finally {
if (cursor != null)
cursor.close();
}
return rawContactId;
}
好的,让我们试试这个…
private static final Uri DATAGROUP_CONTENT_URI = ContactsContract.Data.CONTENT_URI.buildUpon().appendQueryParameter(Data.MIMETYPE, GroupMembership.CONTENT_ITEM_TYPE).build();
public static void querytGroups(Context context) {
final ContentResolver resolver = context.getContentResolver();
long groupid=getGroupId(resolver, "Family");
final Cursor c = resolver.query(DATAGROUP_CONTENT_URI, DataQueryForContactsInGroup.PROJECTION, DataQueryForContactsInGroup.SELECTION, new String[] {ContactsContract.CommonDataKinds.GroupMembership.CONTENT_ITEM_TYPE, String.valueOf(groupid)}, null);
try {
while (c.moveToNext()) {
final long rawContactId = c.getLong(DataQueryForContactsInGroup.RAW_CONTACT_ID);
//do something
}
}finally {
c.close();
}
}
private static long getGroupId(final ContentResolver resolver, String groupName) {
long groupid = -1;
Cursor cur = null;
try {
cur = resolver.query(Groups.CONTENT_URI, DataQueryForGroup.PROJECTION, DataQueryForGroup.SELECTION, new String[]{"%"+groupName+"%"}, null);
while (cur.moveToNext()) {
return groupid= cur.getLong(DataQueryForGroup.GROUP_ID);
}
}finally {
if (cur!=null) cur.close();
}
return groupid;
}
private interface DataQueryForGroup {
public final static String[] PROJECTION = new String[] {Groups._ID};
public static final String SELECTION = Groups.TITLE+" LIKE ?";
public final static int GROUP_ID = 0;
}
private interface DataQueryForContactsInGroup {
public final static String[] PROJECTION = new String[] { Data.RAW_CONTACT_ID };
public static final String SELECTION = "("+Data.MIMETYPE + "=?) and ("+ ContactsContract.CommonDataKinds.GroupMembership.GROUP_ROW_ID+ "=?)";
public final static int RAW_CONTACT_ID = 0;
}
请考虑,如果你的谷歌帐户不是英文的,你需要寻找合适的组名