使用Regex在字符串中提取浮点数

Question

我有以下字符串列表

List = ['A = -25.47 dBm' , 'B = -47.35 dBm' , 'A = -26.54 dBm' , 'B = -32.35 dBm', 'A = 27.95 dBm' , 'B = -64.11 dBm' , 'A = -45.11 dBm' , 'B = -18.67 dBm']

我想提取A的值列表的值，B的值，并列出该

的列表

我尝试了以下

#First I joined the data into a string
S = ' '.join(List)
re.findall(r"A =  ([-+]?d*.d+|d+) dBm" , S)

似乎不起作用

预期结果

A_list = [-25.47,-26.54, 27.95,-45.11] 
B_list = [-47.35,-32.35,-64.11,-18.67]

Answer 1

您可以使用re和collections.defaultdict：

import re, collections
l = ['A = -25.47 dBm' , 'B = -47.35 dBm' , 'A = -26.54 dBm' , 'B = -32.35 dBm', 'A = 27.95 dBm' , 'B = -64.11 dBm' , 'A = -45.11 dBm' , 'B = -18.67 dBm']
d = collections.defaultdict(list)
for i in l:
  a, b = re.findall('^w+|[-d.]+', i)
  d[a].append(float(b))
A_list, B_list = d['A'], d['B']

输出：

[-25.47, -26.54, 27.95, -45.11]
[-47.35, -32.35, -64.11, -18.67]