jQuery文件上传并将文件名放入数据库中

Question

我有这个 AJAX 消息表单：

.HTML：

<form class="" id="message-form" action="message-send.php" method="POST">
  <div class="form-group">
    <textarea name="message" id="message-field" rows="3" class="form-control message-field"></textarea>
  </div>
  <div class="form-group">
    <input type="file" id="file" name="file">
  </div>
  <div class="form-group text-right">
    <input type="submit" id="submit" class="btn btn-success btn-sm msg-send" value="Envoyer" disabled>
  </div>
</form>

JavaScript：

var message_form = $('#message-form');
message_form.submit(function (e) {
    e.preventDefault();
    $('#submit').attr('disabled', true).val('Sending...');
    $.ajax({
        type: message_form.attr('method'),
        url: message_form.attr('action'),
        data: message_form.serialize(),
        success: function (data) {
            console.log('Submission was successful.');
            console.log(data);
            $('#message-field').val('');
            $('#submit').val('Send');
        },
        error: function (data) {
            console.log('An error occurred.');
            console.log(data);
        },
    });
});

.PHP：

require 'config.php';
$message = $_POST['message'];
$query = 'INSERT INTO messages (time, from, to, message, file) VALUES (?, ?, ?, ?, ?)';
if (!($stmt = $mysqli->prepare($query))) {
    echo $mysqli->error;
}
$stmt->bind_param('iiiss', $time, $from, $to, $message, $file);
$stmt->execute();
$stmt->close();
$mysqli->close();

现在我需要的是：

• 使用 AJAX 上传文件
• 将文件按原样存储到具有相同名称的"/uploads/">
• 将文件名与消息一起放在数据库中

注意：表单已经运行良好(提供的代码只是一个最小版本(我只需要处理文件。

Answer 1

您尚未在 ajax 请求中包含 mimetypes。 mimeTypes: "multipart/form-data" ajax 中添加这个

尝试使用表单数据发送输入值

var message_form = $('#message-form');
message_form.submit(function (e) {
    e.preventDefault();
    $('#submit').attr('disabled', true).val('Sending...');
       var message_form = $('#message-form');
       var file = $('#file');
       var formdata = new FormData();
       formdata.append('file', file.files[0]);
       formdata.append('message', $('#message-field').val());
       $.ajax({
            type: message_form.attr('method'),
            url: message_form.attr('action'),
            mimeTypes: "multipart/form-data,
            data: formdata,
            async: true,
            contentType: false,
            processData: false,
            beforeSend: function(){
            },
            success: function (data) {
                console.log('Submission was successful.');
                console.log(data);
                $('#message-field').val('');
                $('#submit').val('Send');
            },
            error: function (data) {
                console.log('An error occurred.');
                console.log(data);
            },
        });
    }