我想在时间延迟下绘制多行。我正在使用循环进行X和Y坐标。这是我的代码：
import pygame,sys
pygame.init()
screen = pygame.display.set_mode((1600, 900))
RED = (230, 30, 30)
background_image = pygame.image.load("image.jpg")
background_image = pygame.transform.scale(background_image, (1600,900))
clock = pygame.time.Clock()
# Main loop
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
sys.exit()
# Fill the background
screen.blit(background_image, [0, 0])
x= [60,70,80]
y= [500,600,700]
for x,y in zip(x,y):
pygame.draw.line(background_image, RED,(x,y),(900,1280), 10)
pygame.display.update()
pygame.time.delay(10)
# Update the screen
pygame.display.flip()
`
您必须在screen而不是background_image上绘制行。500毫秒为半秒（10毫秒是A bit 快速）。另外，不要为列表和坐标使用相同的变量名称。
import sys
import pygame
pygame.init()
screen = pygame.display.set_mode((1024, 768))
RED = (150, 30, 30)
# Replaced the image with a Surface to test the code.
background_image = pygame.Surface((1024, 768))
background_image.fill((50, 90, 140))
clock = pygame.time.Clock()
xs = [60, 70, 80, 90]
ys = [500, 600, 700, 800]
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
sys.exit()
screen.blit(background_image, [0, 0])
for x, y in zip(xs, ys):
# Draw the lines on the screen not the background.
pygame.draw.line(screen, RED, (x, y), (400, 480), 10)
pygame.display.update()
pygame.time.delay(500)
pygame.display.flip()
clock.tick(30)
此版本仍然有问题，因为您停止执行其余主循环运行时。这意味着您不能在此期间退出或处理其他事件。
使用计时器变量，我为您提供了一个更复杂的示例。您从中减去三角洲时间（自上次滴答以来通过的时间），当它低于0时，您将另一个坐标添加到用于图纸的列表中。
import sys
import pygame
pygame.init()
screen = pygame.display.set_mode((1024, 768))
RED = (120, 30, 30)
background_image = pygame.Surface((1024, 768))
background_image.fill((50, 90, 140))
clock = pygame.time.Clock()
xs = [60, 70, 80, 90]
ys = [400, 500, 600, 700]
xys = zip(xs, ys)
startpoints = [] # This holds the current startpoints.
dt = 0
timer = 500 # A countdown timer.
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
sys.exit()
timer -= dt # Decrease timer.
if timer <= 0: # If timer < 0 append the next xy coords.
try:
# `next` just gives you the next item in the xys zip iterator.
startpoints.append(next(xys))
# When the zip iterator is exhausted, clear the
# startpoints list and create a new zip iterator.
except StopIteration:
startpoints.clear()
xys = zip(xs, ys)
timer = 500 # Reset the timer.
screen.blit(background_image, [0, 0])
for x, y in startpoints: # Loop over the available startpoints.
pygame.draw.line(screen, RED, (x, y), (400, 480), 10)
pygame.display.flip()
dt = clock.tick(30)
，或者您可以使用自定义事件和pygame.time.set_timer：
add_coord_event = pygame.USEREVENT + 1
pygame.time.set_timer(add_coord_event, 500)
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
sys.exit()
if event.type == add_coord_event:
try:
startpoints.append(next(xys))
# When the zip iterator is exhausted, clear the
# startpoints list and create a new zip iterator.
except StopIteration:
startpoints.clear()
xys = zip(xs, ys)
编辑：或者更好，或者更好，只需在while循环之前创建起点列表，然后使用i切片。然后，您不必将项目从迭代器移动到列表。
xs = [60, 70, 80, 90]
ys = [400, 500, 600, 700]
startpoints = list(zip(xs, ys))
i = 0 # Current index, used to slice startpoints.
clock = pygame.time.Clock()
increase_index_event = pygame.USEREVENT + 1
pygame.time.set_timer(increase_index_event, 500)
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
sys.exit()
if event.type == increase_index_event:
i += 1
i %= len(startpoints) + 1 # Keep i in the correct range.
screen.blit(background_image, [0, 0])
for x, y in startpoints[:i]:
pygame.draw.line(screen, RED, (x, y), (500, 580), 10)
pygame.display.flip()
clock.tick(30)
您可以使用time.wait()，但这只会冻结您的程序，或者您可以拥有一个可以绘制该行的时间的变量。基本上，当您绘制第一行时具有nextLine = time.clock()+1，并且在循环中说if time.clock > nextLine:，然后绘制下一行。